Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
Answer:to export the PivotTable data into another worksheet
Explanation:hope this helps :D
Computer Chips. / SILICON. This is just an educated guess
If fhun gftrfjjtcbjjbsufcghtfghyrssfbkoire crazy ahh young man
Answer:
B
Explanation:
i’m an information technology student and as I remember we used this name
