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2 years ago

11

What is the volume of the pool?

1 answer:

Fofino [41]2 years ago

5 0

Answer: 7.5

Step-by-step explanation:

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Evaluate A2 for A = -4

vekshin1

Hello there!

Evaluate a² for a = -4

The first step we need to do is replace a by -4

So we have (-4)²

Now what you have realize is that we need to multiply -4 by itself twice.

So it should looks like this:

-4 * -4

The rules says that when we have minus * minus, the answer is positive.

So we have -4 * -4 = 16

Answer: 16

I hope this helps!

Please let us know if you have other questions.

#Garebear

8 0

2 years ago

3. What are the next three terms of the sequence. 6, 12, 18, 24, ...?

Wewaii [24]

Answer:

O 30, 36, 42

Step-by-step explanation:

6 = 1 × 6, 12 = 2 × 6, 18 = 3 × 6, 24 = 4 × 6, ? = 5 × 6 = <u>30</u>, ? = 6 × 6 = <u>36</u>, ? = 7 × 6 = <u>42</u>

6 0

2 years ago

. Evaluate tan(α + β) = sin(????+????) / cos(????+????) to show tan(???? + ????) = tan(????)+tan(????????) / 1−tan(????) tan(???

grandymaker [24]

Answer with Step-by-step explanation:

We are given that

$tan(\alpha+\beta)$

$\frac{sin(\alpha+\beta}{cos(\alpha+\beta)}$

By using formula $tan x=\frac{sin x}{cos x}$

$\frac{sin\alpha cos\beta+sin\beta cos\alpha}{cos\alpha cos\beta-sin\alpha sin\beta}$

By using property: $sin(x+y)=sin x cosy+cos x sin y$

$cos(x+y)=cos x cosy-sin x siny$

Divide numerator and denominator by $cos\alpha cos\beta$

Then, we get

$\frac{\frac{sin\alpha}{cos\alpha}+\frac{sin\beta}{cos\beta}}{1-\frac{sin\alpha sin\beta}{cos\alpha cos\beta}}$

$tan(\alpha+\beta)=\frac{tan\alpha+tan\beta}{1-tan\alpha tan\beta}$

Hence, proved

Substitute $\alpha=\beta$

Then we get

$tan 2\alpha=\frac{tan\alpha+tan\alpha}{1-tan^2\alpha}$

$tan(2\alpha)=\frac{2tan\alpha}{1-tan^2\alpha}$

Hence, proved.

3 0

3 years ago

Math help me out this is tricky man hurry solve both

nekit [7.7K]

Answer:

1) a , b , c , e are ans....

2) a.F b.T c.F d.T

8 0

2 years ago

Evaluating Piecewise Functions:<br><br> Please explain your answer. Thank you.

Mama L [17]

Answer:

f(-1) is undefined.

Step-by-step explanation:

We are given:

$f(x) = \left\{ \begin{array}{ll} -3x-11 & \quad x \leq -5\\ 2 & \quad x > 5 \end{array} \right.$

And we want to find f(-1).

The piecewise function only gives us values for <em>x-</em>values less than or equal to -5 or greater than 5.

Since -1 is fits neither of those conditions, it is not defined.

Our answer is undefined.

3 0

2 years ago