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tankabanditka [31]
3 years ago
15

1 (66 divided by 6)+31"

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

1. 42

2. 6

3. 18

4. 0

5. - 2

Step-by-step explanation:

Use BIDMAS

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Please help me answer ASAP if you hurry I’ll mark you brainliest
Ket [755]

Answer:

a c d

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
!NEED HELP!<br><br>SOLVING WITH SUBSTITUTION METHOD<br><br>6x-2y=5<br>y=3x+7​
Lady bird [3.3K]

Step-by-step explanation:

6x-2y=5 ........... Equation 1

y=3x+7 ............. Equation 2

Substitute y that's Equation 2 into equation 1 and solve for x

That's

6x - 2( 3x + 7) = 5

6x - 6x - 14 = 5

6x - 6x = 14 + 5

6x - 6x = 19

0x = 19

Divide by 0

x is undefined

Since x is undefined y is also undefined which means that the system has no solutions

Hope this helps you

6 0
4 years ago
Which best describes your understanding of theoretical and experimental probability
Lady_Fox [76]
<span>Probability is usually calculated as the number of ways an event has occurred over the overall number of outcome. Theoretical probability is therefore the probability where an event is expected to happen whereas experimental probability is an event that certainly happens.</span>
7 0
4 years ago
What is (c+d) to the power of 3​
goblinko [34]

Answer:

c³ + cd³ + 3c²d + 3cd²

Step-by-step explanation:

(c+d)^3 is worded as <em>c plus d quantity cubed</em> which doesn't mean you cube everything inside. It means you multiply the quantity by itself 3 times.

(c+d)(c+d)(c+d)

<em>You can only multiply 2 at a time so do the first two then the result and the third one.</em>

<em>Distribute everything in one quantity to the other so </em><em>c*c = c^2 and c*d = cd</em>

= (c^2 + 2cd + d^2)(c+d)

= c^3 + c^2d + 2c^2d + 2cd^2 + cd^2 + cd^3

<em>Combine like terms</em>

= c³ + 3c²d + 3cd² + cd³

3 0
3 years ago
What is 12% of 507<br> OA. 6<br> OB.<br> 7<br> O c.<br> 10<br> OD<br> 12
mamaluj [8]
10 and I know this because I just looked it up hopefully you have a great rest of ur day
4 0
3 years ago
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