Answer:
1. t=240
2.t/3=(t/4)+20
Step-by-step explanation:
<span>-6f+13=2f-11
-6f - 2f = -11 - 13
-8f = -24
f = 3</span>
Answer:
No solution
Step-by-step explanation:
since it equals a negative 3 in the original equation it cannot be solved
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
the negative - positive
- 24/-4
24/4
6
