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shepuryov [24]
3 years ago
6

The absolute value of a number is always non-negative. A. True B. False

Mathematics
2 answers:
avanturin [10]3 years ago
7 0

Answer:

\Large \boxed{\sf A. \ True}

Step-by-step explanation:

Absolute value is the number's distance from zero.

The absolute value of a number is always non-negative because distance is not negative (without considering direction).

Fittoniya [83]3 years ago
4 0

Answer:

ios a

Step-by-step explanation:

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Point (-4,-8) Reflected across the x-axis
kkurt [141]

Answer:

(-4 , 8)

Step-by-step explanation:

The x-axis is the horizontal line. In this case, if you are reflecting over the x-axis, you are flipping the sign of the y-coordinate.

Same with the y-axis. If you are reflecting over the y-axis, you are flipping the sign of the x-coordinate.

In this case, reflect across the x-axis. Flip the sign of the y: (x , y)

(-4 , -8) reflected over the x-axis is (-4 , 8).

~

8 0
3 years ago
Simplify.
Sidana [21]
<h3>Answer: 3\sqrt{7}</h3>

3*sqrt(7)

3 times the square root of 7

====================================================

Explanation:

I'm assuming the V stands for square root. You can write sqrt(63).

\sqrt{63} = \sqrt{9*7}\\\\\sqrt{63} = \sqrt{9}*\sqrt{7}\\\\\sqrt{63} = 3\sqrt{7}

The idea is to factor 63 in such a way that one factor is the largest perfect square possible, that way we can pull the root apart to simplify as shown above. The rule I used for the second step is \sqrt{x*y} = \sqrt{x}*\sqrt{y}

5 0
3 years ago
Not sure about these either...
harina [27]
5 is a and 6 is also a
6 0
3 years ago
Find the area of the shaded region below.
pickupchik [31]

Answer:

145

Step-by-step explanation:

yeah-ya...... right?

5 0
2 years ago
If rectangle ABCD, defined by the coordinates A(0, 0), B(0, -4), C(-2, -4), D(-2, 0), is dilated by a scale factor of 2, with re
notsponge [240]

Answer:

D) (-2, -4).

Step-by-step explanation:

Let (x, y) be the center of dilation. Imagine that (x, y) is the center of origin of a new Cartesian Plane. What would the coordinates of point A and A' on the new plane?

  • A: (0 - x, 0 - y) ⇒ (-x, -y).
  • A': (2 - x, 4 - y).

Dilating (-x, -y) about the "origin" of the new plane by a factor of two will give the point (-{\bf 2}x, -{\bf 2}y), also on the new plane.

For coordinates of A' on the original plane,

(-{2}x, -{2}y) = (2 - x, 4 - y).

As a result,

\left \{ \begin{array}{l}-2x = 2 - x\\-2 y = 4 - y\end{array}.

\left \{ \begin{array}{l}-x = 2\\- y = 4\end{array}.

\left \{ \begin{array}{l}x = -2\\y = -4\end{array}.

In other words, {\bf (-2, -4)} is the center of dilation.

6 0
3 years ago
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