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9966 [12]
3 years ago
13

Which source is NOT a valid data source for a mail merge?

Computers and Technology
2 answers:
sattari [20]3 years ago
8 0

Answer:

database

Explanation:

From the different options listed below the one that is not a valid data source for mail merge is a database. This is because mail merge uses all the different Microsoft Word and Microsoft Excel types of documents, these include Outlook contacts , Excel worksheet , and even PDF document. Databases on the other hand are server-side programs that contain a wide range of information but are not considered to be a specific document type and therefore not accepted for mail merge.

VladimirAG [237]3 years ago
8 0

Answer:

the answer is AAAAAAAAAAA

Explanation:

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Create a method remove Evens that removes all even elements from an ArrayList of
igor_vitrenko [27]

Answer:

#include <iostream>

# include <conio.h>

using namespace std;

main()

{

int size;

cout<<"enter the size of array";

cin>>size;

int a[size],b[size];

for (int i=0;i<size;i++)

{

cout<<"enter the value in array a"<<i;

cin>>a[i];

}

for (int k=0;k<=size;k++)

{

{

 if (a[k]%2==0)

 {

  for (int l=k; l<=size;l++)

  {

   

  a[l]=a[l+1];

   

   

     }

     size=size-1;

 }

   

}

}

cout<<"\nArray list without even";

for(int j=0;j<size+1;j++)

{

cout<<"\n"<<a[j];

}

getch();

}

Explanation:

There is an array taken of variable size, the program has been written to delete the even elements from the array list. In this program "size " is the integer variable that is taken to mention the total elements of the array. Then enter the values on different index of array.

After that program find the even values and then delete these values. After the operation new array will be displayed on output.

3 0
4 years ago
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