Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:
Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:
So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110
C) Between 80 and 120
D) less than 80
E) Between 70 and 100
F) More than 130
4-0-0
2-1-1
1-2-1
1-0-3
0-1-3
Those are just the ones I can think of so about 5 ways
So, she buys 16 bags, each of them weights
pounds.
to find how many pounds of soil she bought, we have to multiply:
16*
=//16 is equal to 8*2, so we can simpify:
2*
which is 2*5=10
so in the end she bought 10 pounds of soil!
A is correct, D, And E.....
A) area of square = base*height/////Triangle= 0.5*base*height
=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)
B) a^2+b^2=c^2 (pythagorean theorem)
((27^2/3)*(16^1/4))^2 + (27^1/3)*(16^3/4)
(9*2=(18^2))=324 + (3*8= 24^2)= 576
324+576= 900
(900)^1/2= 30
hypotenuse= 30
C)( a^2/3*b^1/2)= 36*2(two sides)= 72
(a^1/3b^3/4)=24
(a^2/3*b^1/4)= 18
72+24+18+30(hypotenuse)= 144=perimeter
