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3 years ago

Which situation is represented by the equation x+10=26?

Mathematics

2 answers:

sertanlavr [38]3 years ago

8 0

the situation is addition the answer is 16 i think

zhuklara [117]3 years ago

6 0

Answer:

Step-by-step explanation:

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Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

Help!!!!! I'm timed!!!!!

djverab [1.8K]

Answer:

Option C, $28$

Step-by-step explanation:

$2\sqrt{98} * 2$

$2\sqrt{7^2*2} *\sqrt{2}$

$14\sqrt{2} * \sqrt{2}$

$14*2$

$28$

Answer: Option C, $28$

5 0

3 years ago

Someone please helppp ! i’ll give brainliest to the right answer !

Nuetrik [128]

Answer:

The function is 2 I believe

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Using pemdas please

Bond [772]

$4^{3}+2(8)=80$

Solution:

Given expression:

$4^{3}+2(8)$

<u>Expansion of PEDMAS: </u>

Parenthesis, Exponents, Division, Multiplication, Addition, Subtraction.

To solve the given expression using pedmas rule.

First solve the expression with parenthesis.

$4^{3}+2(8)=4^{3}+16$

Next do the exponents.

$4^{3}+2(8)=64+16$

Finally do the addition.

$4^{3}+2(8)=80$

Hence the answer is 80.

6 0

3 years ago

Read 2 more answers

Iam a number less then 3000. When u divide me by 32 my remainder is 30. When u divide me by 58 my remainder is 44. What number a

forsale [732]

32a+30=YOU,
58b+44=YOU, a,b and YOU are integers; YOU<3000.

YOU can be 798, 1726, or 2654.

Download pdf

4 0

3 years ago