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2 years ago

50 pts please help asap (:

Mathematics

1 answer:

andriy [413]2 years ago

3 0

Answer:

d. 8 units

Step-by-step explanation:

If AC = 16 units then the length of CB is 8 units because DB is perpendicular bisector from the centre of circle.

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I Need HelpAsap please I will mark you brainlist

Pani-rosa [81]

Lets say x = 89.99 and y = 56.49

P% * x = y

P% = y/x

56.49/89.99 = 0.6277

0.6277 * 100 = 62.77

But because we are looking for how much off the sale is:

100% - 62.77%

= 37.23%

The sale price is 37.23% off.

7 0

2 years ago

In this problem, you will use undetermined coefficients to solve the nonhomogeneous equation y′′+4y′+4y=12te^(−2t)−(8t+12) with

Zarrin [17]

First check the characteristic solution:

y'' + 4y' + 4y = 0

has characteristic equation

r ² + 4r + 4 = (r + 2)² = 0

with a double root at r = -2, so the characteristic solution is

$y_c = C_1e^{-2t} + C_2te^{-2t}$

For the particular solution corresponding to $12te^{-2t}$ , we might first try the ansatz

$y_p = (At+B)e^{-2t}$

but $e^{-2t}$ and $te^{-2t}$ are already accounted for in the characteristic solution. So we instead use

$y_p = (At^3+Bt^2)e^{-2t}$

which has derivatives

${y_p}' = (-2At^3+(3A-2B)t^2+2Bt)e^{-2t}$

${y_p}'' = (4At^3+(-12A+4B)t^2+(6A-8B)t+2B)e^{-2t}$

Substituting these into the left side of the ODE gives

$(4At^3+(-12A+4B)t^2+(6A-8B)t+2B)e^{-2t} + 4(-2At^3+(3A-2B)t^2+2Bt)e^{-2t} + 4(At^3+Bt^2)e^{-2t} \\\\ = (6At+2B)e^{-2t} = 12te^{-2t}$

so that 6A = 12 and 2B = 0, or A = 2 and B = 0.

For the second solution corresponding to $-8t-12$ , we use

$y_p = Ct + D$

with derivative

${y_p}' = C$

${y_p}'' = 0$

Substituting these gives

$4C + 4(Ct+D) = 4Ct + 4C + 4D = -8t-12$

so that 4C = -8 and 4C + 4D = -12, or C = -2 and D = -1.

Then the general solution to the ODE is

$y = C_1e^{-2t} + C_2te^{-2t} + 2t^3e^{-2t} - 2t - 1$

Given the initial conditions y (0) = -2 and y' (0) = 1, we have

$-2 = C_1 - 1 \implies C_1 = -1$

$1 = -2C_1 + C_2 - 2 \implies C_2 = 1$

and so the particular solution satisfying these conditions is

$y = -e^{-2t} + te^{-2t} + 2t^3e^{-2t} - 2t - 1$

$\boxed{y = (2t^3+t-1)e^{-2t} - 2t - 1}$

7 0

2 years ago

What shape can be created by the given net? triangular pyramid wedge triangular prism cone

Juliette [100K]

Answer:

triangular prism

Step-by-step explanation:

6 0

2 years ago

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100 decreased by 50% and 150 decreased by 60% Compare

sertanlavr [38]

Answer: 60% = 60/100 = 60 ÷ 100 = 0.6. 100% = 100/100 = 100 ÷ 100 = 1.

Step-by-step explanation: Decrease number by 60% of its value. Percentage decrease = 60% × 150 New value = 150

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1 year ago

Simplify fully: (Question is on the photo).

dedylja [7]

Step-by-step explanation:

$4(x + 3) {z}^{ - 1}$

6 0

3 years ago

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