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GaryK [48]
3 years ago
8

What is the class boundaries of 90-99

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0
89.5, 99.5 (hope this helped)
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antiseptic1488 [7]

Answer:

(x-3)(x+2) i.e. x2 - x -6 i.e. p = -1 and q = -6

Step-by-step explanation:

7 0
3 years ago
The central angle of a minor arc is an acute angle.
Nostrana [21]
<span>The central angle in a minor arc is acute. In a minor arc, the angle must be less than 180˚. However, it doesn't have to be less than 90˚. So the central angle is sometimes acute. 

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3 0
3 years ago
Gravity on the Moon is much weaker than on Earth. The expression below can be used to approximate the time in seconds it takes f
melisa1 [442]
It will take an object dropped from a height of 50 meters √50/0.82 = 8.62 seconds to land on the moon.
7 0
2 years ago
The dimensions of a rectangular garden were 5m by 12m. Each dimensions was increased by the same amount. the garden has an area
Alex_Xolod [135]
Let's say, the amount that each side was increased was "a"
so, it was 5 wide and 12 long, now it's 5+a wide and 12+a long

we know the area is 120, so whatever "a" is, we know that

(5+a)(12+a) = 120

so   \bf (5+a)(12+a) = 120\implies 60+17a+a^2=120&#10;\\\\\\&#10;a^2+\underline{17} a\underline{-60}=0\qquad \qquad &#10;\begin{cases}&#10;20\cdot -3\implies \underline{-60}\\\\&#10;20-3\implies \underline{17}&#10;\end{cases}

use those factors, solve for "a"
4 0
3 years ago
The third term of a sequence is 120. The fifth term is 76.8. Write an explicit rule representing this geometric sequence.
juin [17]
The nth term of the geometric sequence is:
an=ar^(n-1)
where 
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
120=ar^2
a=120/(r^2)....i
also:
76.8=ar^(5-1)
76.8=ar^4
a=76.8/r^4.....i
thus from i and ii
120/r^2=76.8/r^4
from above we can have:
120=76.8/r²
120r²=76.8
r²=76.8/120
r²=0.64
r=√0.64
r=0.8
hence:
a=120/(0.64)=187.5
therefore the formula for the series will be:
an=187.5r^0.8
4 0
3 years ago
Read 2 more answers
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