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GaryK [48]
3 years ago
8

What is the class boundaries of 90-99

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0
89.5, 99.5 (hope this helped)
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Calculate the area of the quarter circle estimate using 3.14 for pi
mars1129 [50]

The area of the quarter circle with radius 3ft is 7.065 ft^2

Area of a quarter circle is given by the formula:

Area = \frac{\pi r^2}{4}

Where r represents the radius of the circle

In the quarter circle shown, the radius, r = 3 feet

π  =  3.14

Substitute π = 3.14 and r = 3 into the formula Area = \frac{\pi r^2}{4}

Area = \frac{3.14 \times 3^2}{4}\\\\Area =   \frac{3.14 \times 9}{4}\\\\Area =  \frac{28.26}{4}\\\\Area = 7.065 ft^2

The area of the quarter circle with radius 3ft is 7.065 ft^2

Learn more here: brainly.com/question/25843249

6 0
3 years ago
1.which side of AFED does AB in AABC correspond to?
erma4kov [3.2K]

Rotate one of them so the right angle is in the same orientation as the other one.

1. AB = DE

2. CB = FE

3. AC = DF

4. Compare the length of two known sides: cb and EF

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8/3 = 2 2/3 scale factor

5. Ab is side de. Multiply the length of ab by the scale factor:

4 x 2 2/3 = 10 2/3

6. FD = sqrt ( 10 2/3^2 + 8^2)

FD = 13 1/3

6 0
3 years ago
10 times as many as _ hundreds is 60 hundreds or _ thousands
vovangra [49]
60 hundreds = 60 * 100 = 6,000  ( six thousands )
10 * 600 = 6,000 ( 10 times as many as 600 is 6,000 - six thousands )
Answer:
10 times as many as 6 hundreds is 60 hundreds or 6 thousands.  
6 0
3 years ago
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Given: ABC , BD is an<br> altitude to side AC, &amp; D is a midpoint<br> Prove: AB BC
Over [174]

Answer:

steps below

Step-by-step explanation:

BD⊥AC    ∠ADB = ∠CDB = 90°

D is mid-point: AD = CD

BD = BD

ΔADB ≅ ΔCDB

AB = BC

5 0
3 years ago
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!PLEASE HELP! A square concrete foundation was prepared as a base for a large cylindrical gasoline tank.
nikdorinn [45]
Answer: B, you have to multiply the (A) area by 10 and then you divide the circular base of the tank, then you add those 2 answers and you have it as the function of the radius!
7 0
3 years ago
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