Need help its my last question and i need a 100 to bring up my grades from a B to an A

Help please this was due yesterday (i have more needing done)

prohojiy [21]

Answer:

the answer is x=6

Step-by-step explanation:

5x+4+8x-3=79

13x+1=79

13x=78

x=6

7 0

4 years ago

–20, - 12,5, 22, . . . An= A50=

marshall27 [118]

Answer:

an = 17n - 46

a50 = 804

Step-by-step explanation:

-29, -12, 5, 22, ...

Subtract each number from the next one.

-12 - (-29) = 17

5 - (-12) = 17

22 - 5 = 17

The common difference is 17. This is an arithmetic sequence which starts with -29, and in which each subsequent value is 17 more than the previous value.

a1 = -29

a2 = -29 + 17

a3 = -29 + 2(17)

a4 = -29 + 3(17)

Notice that for each term, you have -29 and something added to it. What you add to -29 is 17 multiplied by 1 less than the number of the term. For term 1, 1 less than 1 is 0. You add 0 * 17 to -29 and get -29. term 1 is -29. For term 2, 1 less than 2 is 1. You add 1 * 17 to -29 and get -12, etc.

For term n, 1 less than n is n - 1. Add (n - 1) * 17 to -29 to get term n.

an = -29 + 17(n - 1)

This formula can be simplified.

an = -29 + 17n - 17

an = -46 + 17n

an = 17n - 46

a50 = 17(50) - 46

a50 = 804

8 0

3 years ago

Graph this equation of a circle? I'm stuck and I don't know how to approach this math problem.

Soloha48 [4]

First use the distance formula to find the radius of the circle:
d= $\sqrt{ ( x_{2}- x_{1}) ^{2}+ ( y_{2}- y_{1}) ^{2} }$

d= $\sqrt{ (-1-23)^{2}+ (5--2)^{2} }$

d= $\sqrt{ (-24)^{2}+ (7)^{2} }$

d= $\sqrt{ (-24+7)^{2} }$

d= $\sqrt{ (-17)^{2} }$

d=|17|
d=17

Next, find the equation of the circle (use the first picture):
(x+1)^2+(y-5)^2=17^2

Finally, input the equation into a graphing calculator:
(2nd picture)

5 0

3 years ago

Determine the dimensions of a rectangular solid (with a square base) with maximum volume if its surface area is 181.5 square cen

3241004551 [841]

Answer:

The base and height of the solid is 5.5cm

Step-by-step explanation:

Given

$Surface\ Area = 181.5cm^2$

Required

Determine the dimensions that maximizes the volume

Let the base dimension be x and the height be h

The volume is calculated as:

$Volume =x^2 * h$

$Volume =x^2h$

181.5 =x^2h

The surface area (S) is calculated as this:

$S = 2(x^2 + xh + xh)$

$S = 2(x^2 + 2xh)$

$S = 2x^2 + 4xh$

Substitute 181.5 for S

$181.5 = 2x^2 + 4xh$

Make h the subject:

$4xh = 181.5 - 2x^2$

$h = \frac{181.5 - 2x^2}{4x}$

Substitute $h = \frac{181.5 - 2x^2}{4x}$ in $Volume =x^2h$

$V = x^2(\frac{181.5 - 2x^2}{4x})$

$V = x(\frac{181.5 - 2x^2}{4})$

$V = \frac{1}{4}(x)(181.5 - 2x^2)$

$V = \frac{181.5x}{4} - \frac{2x^3}{4}$

$V = \frac{181.5x}{4} - \frac{x^3}{2}$

To get the maximum, we differentiate V with respect to t and set the differentiation to 0

$dV = \frac{181.5}{4} - \frac{3x^2}{2}$

Set to 0

$0 = \frac{181.5}{4} - \frac{3x^2}{2}$

$\frac{3x^2}{2} = \frac{181.5}{4}$

Multiply through by 4

$4 * \frac{3x^2}{2} = \frac{181.5}{4} * 4$

$2*3x^2 = 181.5$

$6x^2 = 181.5$

$x^2 = \frac{181.5}{6}$

$x^2 = 30.25$

$x = \sqrt{30.25$

$x = 5.5$

Recall that:

$h = \frac{181.5 - 2x^2}{4x}$

$h = \frac{181.5 - 2 * 5.5^2}{4 * 5.5}$

$h = \frac{181.5 - 60.5}{22}$

$h = \frac{121}{22}$

$h = 5.5$

So, we have:

$h = 5.5$

$x = 5.5$

Hence, the base and height of the solid is 5.5cm

7 0

3 years ago

Match each word to its definition

maxonik [38]

All i know is that 1 is the fourth option and 3 is the last option. I would assume 2 is the first option, 4 is the second option, 5 is the fifth option, and 6 is the third option, but be sure to check yourself. I hope this helps!

7 0

2 years ago

Read 2 more answers