Answer:
Following are the solution to the question:
Step-by-step explanation:
Answer:
graph A
Step-by-step explanation:
When looking at a graph, there are two different axes. The vertical values--marked by the center up/down line--are "y-values"; and this is called the "y-axis"
The horizontal values--marked by the left/right line--are "x-values"; and this is called the "x-axis"
For the x-axis, values to the left side of the origin (the place where the y-axis and x-axis intercept) are smaller than 0--they are all negative values.
Values to the right side of the origin are positive--greater than 0.
For the y-axis, positive numbers are on the top half [once again, the midpoint / 0 is where the two lines are both = to 0; the origin] and negative numbers are on the bottom half.
Ordered pairs (points) are written as (x,y)
(x-value, y-value)
We are looking for a graph that decreases (along the y-axis), hits a point below the origin, and goes flat/stays constant.
When a graph is decreasing (note: we read graphs from left to right), the line of the graph is slanted downwards (it looks like a line going down).
So, if we look at the graphs, we can see Graph A descending, crossing the y-axis {crossing the middle line /vertical line / y-axis} at a value of -7, and then staying constant (it is no longer increasing or decreasing because the y-values stay the same)
hope this helps!!
The pair of points that are equal to x coordinates is (0,0)
Answer:
The angles formed on line b when cut by the transversal are congruent with ∠2 are 
Step-by-step explanation:
Consider the provided information.
If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .
The angles on the same corners are called corresponding angle.
Alternate Angles: Angles that are in opposite positions relative to a transversal intersecting two lines.
∠2 and ∠6 are corresponding angles
Therefore, ∠2 = ∠6
∠2 and ∠7 are alternate exterior angles
Therefore, ∠2 = ∠7
Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are
