Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
Step-by-step explanation:
a)
total no. of pupils is not more than 24
therefore first equation is
(x+y) ≤ 24. ....(1)
No. of girls exceeding the no. of boys by atleast 4
(y-x) ≥ 4. .....(2)
b) Now Liza chooses 8 boys
Maximum no. of girls = ?
Using first inequality
y+8= 24 ( maximum value of less than or equal to function is equal to itself)
Therefore,
y= 24-8
=16
Minimum no. of girls = ?
Using second inequality
y-8 =4 (minimum value of greater than or equal to function is equal to itself)
Therefore,
y= 4+8
y=12
Answer:
a) 2linear inequalities
(x+y) ≤ 24
(y-x) ≥ 4
b) Max no. of girls = 16
Min no. of girls = 12
Hope it helps...
Simplify by combining the real and imaginary parts of each expression.
1
,
−
96
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