Answer:
Distance between the observer and the red car is 
Step-by-step explanation:
Diameter of field = 500 m
Radius of field =
Let R be the radius and the speed at which the car completes race be w
So,
Car finished 5 laps in minutes = 30
Car finished 1 lap in minutes = 
So, 
Refer the attached figure
Angle between car and observer = wt
So, Distance between the observer and the red car is give as A sin wt
So, Distance between the observer and the red car=
Its 17 15 and 8 i just did that on a test as well
srry no explanation :(
F=ir^t
139=134r^10
139/134=r^10
r=(139/134)^(1/10) then:
f=134(139/134)^(t/10) so in 2014, t=24 so
f=134(139/134)^(2.4)
f≈146 million (to nearest million)
Some will say that you have to use the exponential function, but it really gives you the same answer...even for continuous compounding :)...
A=Pe^(kt)
139=134e^(10k)
139/134=e^(10k)
ln(139/134)=10k
k=ln(139/134)/10 so
A=134e^(t*ln(139/134)/10) when t=24
A=134e^(2.4*ln(139/134))
A≈146 million (to nearest million)
The only real reason or advantage to using A=Pe^(kt) is when you start getting into differential equations...
Answer:
C
Step-by-step explanation:
the volume of the cylinder is 3769.91
the volume of the cube is 1000
so the cylinder's volume is clearly larger than the cube's volume.
Answer:
Step-by-step explanation:
11 is A ( i think)
12 i know is c but if wrong im so sorry
hope this helps
