Well! See ,If the endpoints are (x1,y1) & (x2,y2) then mid-point is given by (x1+x2)/2,
(y1+y2)/2
Here in this question endpoints given for the line segment are (-4,2) , (2,4) so we have to find mid-point for x and y co-ordinates by applying above rule.
So, the mid-point we get is (-4+2)/2 , (2+4)/2.
i.e. (-1,3) which lies in 2nd Co-ordinate!
Hope it helps!!
Times the whole equation by 15 since the LCM of 3 and 5 is 15.
You get: 5p-3p-6= 60
Rearrange to get: 2p=66
p=33
1a) 8 / (1/2) = 16 * 3 = 48
1b) 3sqrt(49) = 3 * 7 = 21
1c) (5+2)(-8) / (-2)^3 -3
(7*-8) / (-8 -3)
-56/-11
56/11
Answer: 14.2 I hope im Right but it’s a simple question
Step-by-step explanation:
Answer:
Answer: 1/12
Step-by-step explanation:
2/5x-4=8-3/5x.
We want to tank x out of the denominator by multiplying x on both sides.
2/5-4x=8x-3/5
Now we simplify
-12x=-1
x=1/12
Put x in the equation to check it
