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Studentka2010 [4]

3 years ago

14

Question 2.

1 answer:

lbvjy [14]3 years ago

7 0

B i tink i am not sure

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Suppose that the sitting back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.

solong [7]

Answer:

$P(X \geq 26.6) = 0.0336$ , which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 24.4, \sigma = 1.2$

In this problem, a value x is significantly high if:

$P(X \geq x) = 0.01$

Using these criteria, is a back-to-knee length of 26.6 in. significantly high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{26.6 - 24.4}{1.2}$

$Z = 1.83$

$Z = 1.83$ has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

$P(X \geq 26.6) = 0.0336$ , which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0

3 years ago

How many are 2 raised to 2 ???

natta225 [31]

Answer:

Step-by-step explanation: 2 raised to 2 or 2^2

is the same as saying 2*2 so 2 raised to 2 or 2^2 is 4

7 0

3 years ago

Read 2 more answers

Liam and his twin sister, Lexi, are frosting cupcakes for a school bake sale. Liam frosts 8 vanilla cupcakes and 16 chocolate cu

nydimaria [60]

They both frosted the same simplified ratio

5 0

3 years ago

The time (in minutes) required to learn the procedure for performing a certain task is uniformly distributed on the interval fro

PtichkaEL [24]

Answer:

a

$P( X > 46) = 0.7 \ minute$

b

$\mu = 42 \ minute$

Step-by-step explanation:

From the question we are told that

The procedure for performing a certain task is uniformly distributed on the interval from( a = 32 )minutes to (b= 52) minutes

Generally the cumulative distribution function for continuous uniform distribution is

$F(x) = \left \{ {{0 \ \ \ \ \ for \ x \ x < a} \atop {\frac{x-a}{b-a} } \ \ for \ a \le x \ge b} \atop {1 \ \ \ \ \ \ \ for \ x > b }\right.$

Generally the probability that it takes more than 46 minutes to learn the procedure is mathematically represented as

$P( X > 46) = F(46) = \frac{46 - 32}{52-32}$

=> $P( X > 46) = 0.7 \ minute$

Generally the average time required to learn the procedure is mathematically represented as

$\mu = \frac{a + b}{2}$

=> $\mu = \frac{32 + 52}{2}$

=> $\mu = 42 \ minute$

3 0

3 years ago

I WILL MARK BRAINIEST <br> please answer question 5

Marat540 [252]

Answer:

a = 150

Step-by-step explanation:

The sum of the internal angles of an octagon is 1080°.

$4a+4(120)=1080$ (There are four $120^{\circ}$ and 4 $a^{\circ}$ , they sum to 1080°)

$4a + 480 = 1080$

$4a = 600$

$a = 150$

Hope this helps :)

4 0

3 years ago

Read 2 more answers