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Damm [24]
3 years ago
11

The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO

Mathematics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

\angle PRQ = 80

Step-by-step explanation:

Given

\angle SPR = 145^o

\angle POT = 115^o

See attachment

Required

Find \angle PRO

First, calculate \angle RPO

\angle RPO + \angle SPR = 180 --- angle on a straight line

So, we have:

\angle RPO + 145 = 180

Collect like terms

\angle RPO = 180 - 145

\angle RPO = 35

Next, calculate PQR

\angle POR + \angle POT = 180

So, we have:

\angle POR + 115 = 180

Collect like terms

\angle POR = 180-115

\angle POR = 65

So, PRO is calculated as:

\angle PRO + \angle POR + \angle RPO = 180 --- angles in a triangle

So, we have:

\angle PRO + 65 + 35= 180

\angle PRO + 100= 180

Collect like terms

\angle PRO = 180-100

\angle PRO = 80

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3 years ago
Is 1/8 - 10× (3/4-3/8X) + 5/8X equivalent to -1/8 × (59-35X)
zubka84 [21]

Yes, Both are equivalent.

<u>Step-by-step explanation:</u>

Step 1:

To find the equality between the given terms Use the BODMAS (Brackets Orders Division Multiplication Addition Subtraction)

RHS SIDE:

(1/8)-10*((3/4)-(3/8*X)+(5/8*X)

Equation after 1st modification

(1/8)-((15/2)-(15/4*X))+(5/8*X)

Equation after Second modification

((1/8)-(15/2)+(15/4*X)+(5/8*X))

Equation after Third modification

LCM 2,4,8 is 8

And taking LCM equation changes to (1-60+30*X+5*X)/8

Equation after Final modification

(-59+35*X)/8        ---------   1

Step 2:

LHS SIDE:

-1/8*(59-35X)

By applying the BODMAS rule in the above equation we will get

(-59+35*X)/8        ------------ 2

From equations 1 & 2, the expression (1/8)-(10*((3/4)-(3/8*X))+(5/8*X) is equivalent to (-1/8)*(59-35*X)

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3 years ago
Help please this problem thank you
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The value of x is 25.
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Answer: false


Step-by-step explanation: the answer is false because suplimentary angled dont add up to 180


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3 years ago
Read 2 more answers
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