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Damm [24]
3 years ago
11

The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO

Mathematics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

\angle PRQ = 80

Step-by-step explanation:

Given

\angle SPR = 145^o

\angle POT = 115^o

See attachment

Required

Find \angle PRO

First, calculate \angle RPO

\angle RPO + \angle SPR = 180 --- angle on a straight line

So, we have:

\angle RPO + 145 = 180

Collect like terms

\angle RPO = 180 - 145

\angle RPO = 35

Next, calculate PQR

\angle POR + \angle POT = 180

So, we have:

\angle POR + 115 = 180

Collect like terms

\angle POR = 180-115

\angle POR = 65

So, PRO is calculated as:

\angle PRO + \angle POR + \angle RPO = 180 --- angles in a triangle

So, we have:

\angle PRO + 65 + 35= 180

\angle PRO + 100= 180

Collect like terms

\angle PRO = 180-100

\angle PRO = 80

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<h3>What is the piecewise defined function behind the graph?</h3>

In this problem we have a <em>piecewise defined</em> function formed by three functions: (i) <em>Linear</em> equation, (ii) <em>Quadratic</em> equation, (iii) <em>Linear</em> equation. The <em>first</em> function is y = 40, for 0 ≤ x < 15.

The <em>second</em> function can be found based on the knowledge of three points:

y = a · x² + b · x + c

(x₁, y₁) = (15, 40)

40 = 225 · a + 15 · b + c

(x₂, y₂) = (45, 2.5)

2.5 = 2025 · a + 45 · b + c

(x₃, y₃) = (65, 20)

20 = 4225 · a + 65 · b + c

And the <em>quadratic</em> equation is y = 0.0425 · x² - 3.8 · x + 87.438, for 15 ≤ x < 65.

And the <em>latter linear</em> equation is:

y = m · x + b

m = (30 - 20)/(90 - 65)

m = 0.4

And the x-intercept is:

b = y - m · x

b = 20 - 0.4 · 65

b = - 6

The <em>linear</em> equation is y = 0.4 · x - 6, for x ≥ 65.

The <em>piecewise defined</em> function is formed by the following three functions: y = 40, for 0 ≤ x < 15, y = 0.0425 · x² - 3.8 · x + 87.438, for 15 ≤ x < 65 and y = 0.4 · x - 6, for x ≥ 65.

To learn more on piecewise defined functions: brainly.com/question/12561612

#SPJ1

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