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3 years ago

13

A rectangle is dilated by a factor of 1/5. The area of the new rectangle is 4 square yards . What could be the dismension of the

original rectangle

1 answer:

katrin [286]3 years ago

4 0

20 square yards is the answer

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If 3n=3a-6,which inequality below will make n a positive number?

kicyunya [14]

If 3n=3a-6 than the answer is B

6 0

3 years ago

How to solve this? Please help!

marta [7]

SinA=8/17, so arcsin(8/17) is your angle of A (around 49 degrees). 90-A is your angle for B

7 0

3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

Find the probability of winning a lottery by selecting the correct six integers, where the order in which these integers are sel

lora16 [44]

Hey there,

The answer is A: 50

:)

5 0

3 years ago

4×<img src="https://tex.z-dn.net/?f=10%5E%7B3%7D" id="TexFormula1" title="10^{3}" alt="10^{3}" align="absmiddle" class="latex-fo

Anettt [7]

4000 (4x10^3) times 400 (4x10^2) is equal to 16x10^5 ( 1,600,000)

5 0

3 years ago