9. Find the perimeter of this figure.

Estimate 10/11 x 1/9. BRAINLIEST TO PEOPLE WHO ANSWER CORRECTLY!!

vovangra [49]

C is the answer to the problem

6 0

2 years ago

You purchase a car in 2010 for $25,000. The value of the car decreases by 14% annually. What would the value of the car be in 20

Fed [463]

Answer: -$6,500

Step-by-step explanation:

Here we could , use the arithmetic progression where

T(2020 - 2010) = a + ( n - 1 )d

T10 = a + ( 10 - 1 )d --------------- 1

a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.

Note since it decreases the common difference d = -$3,500.

Now substitute for the values in the equation above.

T10 = 25,000 + 9 x -3,500

= $25,000 - $31,500

= -$6,500 (deficit )

4 0

2 years ago

Which of the following is closest to the area of the shaded region below?

enot [183]

Answer:

C is the answer

Step-by-step explanation:

Find the area of the whole circle, r=12cm

=pie× radius sq

=3.14×12×12

=452.16cm sq

The are of the smaller circle, r=6cm

=same formula

=3.14×6×6

=113.04cm sq

Subtract them to find the area of the shaded region

452.16 - 113.04

=339.12

Closest is answer is 339 cm sq which is c

Hope it's helpful..... 

5 0

2 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

Solve1 over 25 = 5^x ^+ 4. x = -7/2 x = −6 x = 9/2 x = 2

Basile [38]

The equation seems to be

   1
-------- = 5 ^ (x + 4)
25

In that case, this is the solution, stept by step:

1) factor 25: 25 = 5^2

      1
=> ----------- = 5^(x + 4)
       5^2

2) invert 5^2

=> 5^(-2) = 5^(x+4)

3) Given that the bases are equal, the exponents also have to be equal:

=> - 2 = x + 4

3) transpose +4:

=> - 2 - 4 = x

=> x = - 6

Answer: - 6

6 0

2 years ago

9. Find the perimeter of this figure.​

9. Find the perimeter of this figure.