Answer:
3h²
Step-by-step explanation:
factor or breakdown 3h² : 3 * h * h
factor or breakdown 3h³ : 3 * h * h * h
Now, we can see that 3 * h * h is common so 3h² is the gcf.
Answer:
150 dived by 625 is 0.24 I'm not sure how to explain it
Since 1/8000 is 0.000125, we can move the decimal 4 terms to the right.
So that will be 1.25 • 10^-4
Choice B
Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR
Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)
Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)
Have an awesome day! :)
Answer:
The radius of the inflated spherical balloon is 45 millimeters.
Step-by-step explanation:
Volume of the spherical water balloon = 121,500 pi cubic millimeters
Let the radius of the balloon = r
Now, Volume of a Sphere = 
⇒
On solving for the value of r, we get:
![r^{3} = \frac{121,500\times 3}{4} = 91125\\ \implies r = \sqrt[3]{91125}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%20%3D%20%5Cfrac%7B121%2C500%5Ctimes%203%7D%7B4%7D%20%20%20%3D%2091125%5C%5C%20%5Cimplies%20%20r%20%20%3D%20%5Csqrt%5B3%5D%7B91125%7D)
or, r = 45 millimeter
Hence, the radius of the inflated spherical balloon is 45 millimeters.