Answer:
1st, 2nd, and last.
Step-by-step explanation:
For the first two common rules can be applied such as 
= ![\frac{\sqrt[n]{a} }{\sqrt[n]{b} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5Bn%5D%7Ba%7D%20%7D%7B%5Csqrt%5Bn%5D%7Bb%7D%20%7D)
and that ![\sqrt[n]{\frac{a}{b} } = (\frac{a}{b})^{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%3D%20%28%5Cfrac%7Ba%7D%7Bb%7D%29%5E%7Bn%7D)
and for the last one this is just simplifying the radical and if you factor it you realize that, 
meaning that you can take the radical off of 5/8 and end up with that final answer
Another point on the line is (6,-1)
I think it’s C because a triangle is 180 degrees and it’s a right triangle which means there is a 90 degrees angle + 30 degrees.
90+30=120. 180-120=60
Which means the third angle is 60 degrees
Answer:
Step-by-step explanation:
11) strategy: since they tell us. indirectly, that the length of JK is the same as LM then we can set those two equal, solve for X and then.. when we have X we can figure out the lenght of JK and LM and then just divide that by 2 go get PK ( :0 Player Killer ??? no , not that PK)
solve JK and LM
3x + 23 =9x-19
42 = 6x
7 = x
now that we know x = 7 plug it into either equation to come up with the length of JK or LM . I'll pick JK just b/c it was 1st
3(7) + 23 = JK
21+23 = JK
44 = JK
now take half of 1/2*JK= 22 that is PK ( are you sure that 's not player killer?)
PK = 22
12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB
9x-20 = 5x + 28
4x = 48
X = 12
9(12) -20 = BG
88 = BG
2*88 + AB
176 = AB
13) done
14) strategy: find the angle at L, and that will also be the arc of MK
<em>copy and past the below</em> helpful trig functions into your computer
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
<em>copy and past the above</em> :
use which ever trig function you want , we have all the sides of the triangle, I'll use CAH
Cos(Ф) = 9/15
Ф = arcCos(9/15)
Ф = 53.13010°
arc MK = 53.13010°
15) strategy: arc JK is just 2 times MK
2*MK = 106.26020°
arc MK = 106.26020°
16) find arc JPK strategy: JPK is just the remaining part of a full circle of 360 - MK = 253.7397°
arc JPK = 253.7397°
