Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5

Mathematics

1 answer:

Fynjy0 [20]2 years ago

5 0

Answer:

a(6) = 37.97

Step-by-step explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

a(n) = 5*r^(n - 1).

Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97

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Step-by-step explanation:

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