Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5
1 answer:
Answer:
a(6) = 37.97
Step-by-step explanation:
If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is
a(n) = 5*r^(n - 1).
Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97
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