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julsineya [31]
3 years ago
7

A network of electrical wires will be constructed so that each of the

Mathematics
1 answer:
Ivan3 years ago
6 0

Answer:

D I just did this

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Please help <br><br>tap the picture there are two problem I'm stuck on​
ANEK [815]

Answer:

1. g(x)=2x+1-3 --> g(x)=2x-2, which is also y=2x-2, so you can graph it.

Step-by-step explanation:

Question 1: If f(x) = 2x+1, then you can see that all you have to do is substitute the equation for f(x) into the g(x) equation because g(x)= f(x)-3. So, if you substitute it, the equation will be g(x) = (2x+1) -3, then you just solve the rest of the equation. Put it into slope intercept form, y=mx+b, and then graph the equation.

Sorry, I don't really understand number 2 myself, so hopefully I could help with he first one.

5 0
4 years ago
What is 50,372 in word form
JulsSmile [24]
Fifty thousand and three hundred seventy two
4 0
3 years ago
Read 2 more answers
Part A: Show all work to solve the quadratic equation x2 − 12x + 35 = 0 by factoring. (2 points)
MrRissso [65]

Answer:

  A) x = {5, 7}

  B) The solutions make the equation true.

Step-by-step explanation:

<u>Part A</u>:

To solve this by factoring, you need to find factors of 35 that have a sum of -12. Since 35 is the product of two primes, the search is a short one.

  35 = (-1)(-35) = (-5)(-7)

The corresponding sums are -36 and -12, so the latter factor pair is the one we want. Since the coefficient of x^2 is 1, we can use these numbers directly in the binomial factors:

  x^2 -12x +35 = (x -5)(x -7) = 0

The zero product rule tells us this product is zero only when one of the factors is zero:

  x -5 = 0   ⇒   x = 5

  x -7 = 0   ⇒   x = 7

The two solutions are x=5 and x=7.

__

<u>Part B</u>:

The solutions from part A are the x-intercepts of the graph of the quadratic expression. They are the values of x that make the quadratic expression be zero. That is, they are the values of x that make the equation true.

7 0
4 years ago
Is the set of real numbers closed under addition? Explain why or why not. If it is not closed, give an example​
kicyunya [14]

Answer: Yes, the set of real numbers is closed under addition.

Explanation:

Let x and y be two real numbers. Their sum x+y is some other real number. This is what it means when we say the set of real numbers is closed under addition. Taking any two numbers and adding them will get us some other real number.

There is no way to have x+y be nonreal while x,y are both real.

3 0
3 years ago
How do i wright an algebraic expression from a word problem. Such as "The product of a number w and 737
Artist 52 [7]
The 'product' of two numbers lets you know that you'll be multiplying them. So the product of a number w and 737 is w x 737. That can be rewritten as 737w.
4 0
3 years ago
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