All categories

3 years ago

A football team scored 3 touchdowns, 3 extra points, and 4 field goals.

Mathematics

2 answers:

Mashutka [201]3 years ago

8 0

Answer:

A) 3(T)+3(E)+4(F)=total points

B) 3(6)+3(1)+4(3)=total points

C) 33 points

Vikki [24]3 years ago

3 0

Answer:

A) 3(T)+3(E)+4(F)=total points

B) 3(6)+3(1)+4(3)=total points

C) 33 points

Step-by-step explanation:

T=touchdown

E=extra point

F=field goal

3(T)+3(E)+4(F)=total points

3(6)+3(1)+4(3)=total points

C) 18+3+12=33 points

You might be interested in

Solve each division problem and classify it based on its quotient

Mazyrski [523]

Answer:

1. 6

2. 9

3. 9

4. 6

5. 9

6. 6

Step-by-step explanation:

The answers are in the order listed on your assignment page.

Hope this helps :)

8 0

2 years ago

Need help asap do tonight

aalyn [17]

Answer:

answer and explanation below

Step-by-step explanation:

2.m<x=75(angle on the same line so 180-105)

m<y=105 (vertical angles of the parallelogram are equal)

m<z=75 ( vertical angle of m<x)

3.M<y = 25 ( vertical angle property)

m<z=155( on the same line)

m<z and M,x =155( vertical angles )

8 0

3 years ago

According to a recent survey, the population distribution of number of years of education for self-employed individuals in a c

creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

b) mean and the standard for a random sample of size 49

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4$

c) mean and the standard for a random sample of size 196

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2$

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0

3 years ago

Two bags contain blue and red marbles. The first bag contains 3 blue and 5 red marbles. The second bag contains

dimaraw [331]

Answer: 1/8

<u>Step-by-step explanation:</u>

First Bag and Second Bag

$\dfrac{3\ blue}{8\ total}$ x $\dfrac{2\ blue}{6\ total}$ = $\dfrac{6}{48}$