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2 years ago

600 can be written as 2^a x b x c^d. where a, b, c and d are all prime numbers. find the values of a, b, c and d

Mathematics

1 answer:

Sergeu [11.5K]2 years ago

8 0

Answer:

easy one

Step-by-step explanation:

first factorise 600 as 2*2*2*3*5*5

then write as 2^3 * 3*5^2= 2^a*b*c^d

equating corresponding elements as a=3

b=1and c= 2 is the answer

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10 3/9- 10 2/5 Im to lazy to do it please help me out.

coldgirl [10]

Answer:

$\boxed{ \ - \frac{3}{45} }$

Step-by-step explanation:

10 3/9 - 10 2/5

we need to convert mixed fractions to improper fractions

$10 \frac{3}{9} = \frac{10 \times 9 + 3}{9} = \frac{93}{9}$

$10 \frac{2}{5} = \frac{10 \times 5 + 2}{5} = \frac{52}{5}$

Now, we have 93/9 - 52/5

We need to equate the denominators, before subtracting them.

$\frac{93}{9} - \frac{52}{5} = \frac{93 \times 5}{45} - \frac{52 \times 9}{45}$

$\frac{465}{45} - \frac{468}{45}$

$\frac{ - 3}{45}$

$\boxed{ - \frac{3}{45} }$

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1 year ago

What is the missing constant term in the perfect square that starts with x2 – 16x?

andre [41]

Answer:

Step-by-step explanation:

the expression is

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the number number x = 16

therefore the constant term is (16/ 2)²

= 8²

= 64

the formula being used here is

(x + a)² = x² + 2ax + a²

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3 years ago

kevin has $42 and is saving $8 per week. how many weeks must kevin save in order to have 138 altogether

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Answer:

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Step-by-step explanation:

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