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3 years ago

HELPPP.. ill give the heart and stuff

Mathematics

1 answer:

amm18123 years ago

8 0

Answer:

19) y = 3/2x + 1

20) y = x + 4

21) a: 4/5 b: y = 4/5x + 4 c: 16 feet d: 4

22) a: y + 1 = 4(x - 6)

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bonufazy [111]

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Prove the identity

Troyanec [42]

Answer:

Proved

Step-by-step explanation:

The options are not given. So, I will solve from scratch

Given

$\frac{secx-1}{tan x}= \frac{tanx}{secx+1}$

Required

Prove

Multiply the right-hand side by $\frac{secx + 1}{secx + 1}$

$\frac{secx-1}{tan x} * \frac{secx + 1}{secx + 1}= \frac{tanx}{secx+1}$

Apply difference of two squares on the numerator

$\frac{sec^2 x - 1}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}$

In trigonometry:

$tan^2x = sec^2x - 1$

So, we have:

$\frac{tan^2 x}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}$

$\frac{tan x * tan x}{(tanx)(secx + 1)} =\frac{tanx}{secx+1}$

tan x cancels out

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<em>Proved</em>

3 0

3 years ago

Can someone help me I don't get it

Cerrena [4.2K]

Answer:

6a C; 6b C

8: b.2 and d.15/4

Step-by-step explanation:

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3 years ago

1. What is sin(A)?

STALIN [3.7K]

Answer:

Sin A=0.6

Tan B = 1.3333

Cos C= 0.9231

Cos C= 0.3846

Step-by-step explanation:

For sin A

Sin A= opposite/hypotenuse

Sin A= 3/5

Sin A=0.6

For Tan B

Tan B = opposite/adjacent

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Tan B = 1.3333

For cos C

Cos C = adjacent/hypotenuse

Cos C= 12/13

Cos C= 0.9231

For Cos D

Cos D= adjacent/hypotenuse

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Cos C= 0.3846

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3 years ago

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alukav5142 [94]

80 -224
——
15

976
——
15

Hope this helped

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4 years ago