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2 years ago

Brianna buys 3 packs of balloons for an party. each packs has 60 balloons. how many balloons does Brianna has

Mathematics

2 answers:

weqwewe [10]2 years ago

6 0

Brianna has 180 balloons

Juli2301 [7.4K]2 years ago

5 0

Answer:

180 balloons

Step-by-step explanation:

60 x 3 is 180

or 60+60 = 120 + 60 =180

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Lesson 9: When Are They the Same?

marysya [2.9K]

Answer:

The number of pages that will make the cost of printing equal for both options is 500

Step-by-step explanation:

Please, kindly see the attached file for explanation

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3 years ago

If it took 28 minutes to run 4 miles, then at that rate, how long would it take to run 20 miles?

SSSSS [86.1K]

Answer:

140 minutes

Step-by-step explanation:

After 28 mins you've gone 4 miles, assuming this rate is constant and you dont slow down or speed up, in order to get to 20 miles you will have run 5x as much (20/4 = 5), thus 5x the amount of time (28x5).

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2 years ago

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If two people have a 10% chance of winning what is there combines chance

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Their combined chance of winning is 20%.

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2 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$