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Artist 52 [7]
3 years ago
14

How far in feet will a child on the edge of the merry-go-round travel? If r=6 feet, the angle is 310

Mathematics
1 answer:
goblinko [34]3 years ago
7 0

Answer:

First some theory we need to solve this problem.

For a circle of radius R, the perimeter is:

P = 2*pi*R

where pi = 3.14

If we have a section of this circle, defined by an angle θ, the length of this arc will be:

A = (θ/360°)*2*pi*R

In the case of the problem, the total distance that the child travels is equal to the length of an arc of 310° in a circle of radius r = 6ft.

Using the above formula, we know that the length of this arc is:

A = (310°/360°)*2*3.14*(6ft) = 32.4 ft

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Pls help!! look at photo
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Answer:

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\sf area \ of \ sector: \dfrac{\theta}{360} \pi r^2

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