The following stem-and-lead plot shows the One record attendance for original Charity Drive meetings what is the mode of these v
alues?
A.)48
B.) 84
C.) 70
D.) 66
A.)48
B.) 84
C.) 70
D.) 66
1 answer:
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The correct question is
The raised vegetable garden in Susan's yard is in the shape of a rectangular prism with a volume of 48 cubic feet and a height of 3/4 foot. <span>The base of the rectangular prism is not a square and the width is greater than 2 feet. What is the length and width of the rectangular prism?
let
x-------> the length of the base of the rectangular prism
</span>y-------> the width of the base of the rectangular prism
<span>
we know that
volume of the prism=area of the base*height
volume=48 ft</span>³
<span>height of the prism=3/4 ft
area of the base=volume/height--------> 48/(3/4)---> 48*4/3----> 64 ft</span>²
<span>
area of the base=64 ft</span>²
<span>area of the base=x*y
64=x*y--------> equation 1
y=x+2--------> equation 2
substitute equation 2 in equation 1
64=x*[x+2]-----> 64=x</span>²+2x------> x²+2x-64=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=7.062 ft
y=x+2-----> y=7.062+2-----> y=9.062 ft
the answer is
</span>the length of the base of the rectangular prism is 7.062 ft
the width of the base of the rectangular prism is 9.062 ft<span>
</span>
The raised vegetable garden in Susan's yard is in the shape of a rectangular prism with a volume of 48 cubic feet and a height of 3/4 foot. <span>The base of the rectangular prism is not a square and the width is greater than 2 feet. What is the length and width of the rectangular prism?
let
x-------> the length of the base of the rectangular prism
</span>y-------> the width of the base of the rectangular prism
<span>
we know that
volume of the prism=area of the base*height
volume=48 ft</span>³
<span>height of the prism=3/4 ft
area of the base=volume/height--------> 48/(3/4)---> 48*4/3----> 64 ft</span>²
<span>
area of the base=64 ft</span>²
<span>area of the base=x*y
64=x*y--------> equation 1
y=x+2--------> equation 2
substitute equation 2 in equation 1
64=x*[x+2]-----> 64=x</span>²+2x------> x²+2x-64=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=7.062 ft
y=x+2-----> y=7.062+2-----> y=9.062 ft
the answer is
</span>the length of the base of the rectangular prism is 7.062 ft
the width of the base of the rectangular prism is 9.062 ft<span>
</span>
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Factorise a² - b² :
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Crossed out common factors, (x + a) :
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