its <span>a numerical or constant quantity placed before and multiplying the variable in an algebraic expression</span>
<span>so 3,6,1</span>
Answer:

Step-by-step explanation:
![\displaystyle \frac{3\sqrt{3}}{2}a^2 = A \hookrightarrow \frac{3\sqrt{3}}{2}6^2 = A \\ \frac{3\sqrt{3}}{2}[36] = A; 54\sqrt{3}\:[or\:93,530743609...] \\ \\ \boxed{93,5 \approx A}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7Da%5E2%20%3D%20A%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D6%5E2%20%3D%20A%20%5C%5C%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D%5B36%5D%20%3D%20A%3B%2054%5Csqrt%7B3%7D%5C%3A%5Bor%5C%3A93%2C530743609...%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B93%2C5%20%5Capprox%20A%7D)
I am joyous to assist you at any time.
Answer and explanation:
Given:
Royal soil= $6.50 per pound
Royal peasant = $2 per pound of 10 pounds
Blend total pounds is x+10, price is unknown hence solved below
Using algebra
We find unknown x = number of pounds of royal soil
$6.50(x)+$2(10)=6.50x+20/x+10(x+10)
= 6.50x+20= 6.50x²+85x+200
First subtract 2 revolutions from the - 840 :- (- (840-720) = -120
This gives sin -120 which is in the 3rd quadrant of the unit circle
sin -120 = - sin 60 = - sqrt3/2