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sertanlavr [38]
3 years ago
13

PlZ HELP WILL MARK YOU AS THE BRAINLIEST!

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10

2.  check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9

3. last corner ( -3, 4)

4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42

5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)

6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6

=> area = 3.6x6 =21.6

=> peri = 2x(3.6+6) = 19.2

7. A(-5,4) and B(2,4), AB =  sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base

=> p = peri = 7+ 8.3x2 = 23.6

=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]

             =sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8

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-9 - (18v - 5) = 2(7v - 16) - 3v​
andrezito [222]

Answer:

v = 28/29

Step-by-step explanation:

- 9 - (18v - 5) = 2(7v - 16) - 3v​

- 9 - 18v + 5 = 14v - 32 - 3v

- 18v - 14v + 3v = - 32 - 5 + 9

- 29v = - 28

v = -28 / -29

v = 28/29

6 0
2 years ago
(2-cos^2A)(1+2cot^2A)=(2+Cot^2A)(2-sin^2A)​
fomenos

Answer:

2 sin (2A) cos (2A)^4 + 2cos (2A)

---------------------------------------------------

                 sin (2A)

Step-by-step explanation:

7 0
3 years ago
Write an equation for an exponential growth function where the initial population is 74 and the population quadruples during eac
Liono4ka [1.6K]
If the population quadruples every period say hour, that means the "rate of growth" is 300%, so whatever the current amount, increased by 3 times as much is 4 times the current amount, or a quadrupled amount.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &74\\
r=rate\to 300\%\to \frac{300}{100}\to &3.00\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=74(1+3)^t\implies A=74(4)^t
6 0
3 years ago
Is 1/2 equivalent to 5/8
kompoz [17]
<span>No. 

To check this yourself, you need the denominators to be the same to be able to easily compare the two. 

For example, does 5/8 = 40/64? 

1. Determine what you would need to do to the denominator in 5/8 to make it 64. (Multiply it by 8) 
2. Find what fraction is equal to 1 with a denominator of 8. (8/8) 
3. Multiply the fraction 5/8 by the one you just found (8/8), numerator times numerator, denominator times denominator. 
4. Compare the answer with the second fraction. 

It is important that when you multiply the denominator by any number you multiply the numerator by the same number. This is to preserve the fraction's value. This works because any number divided by itself is equal to 1, AND when you multiply any number by 1 (whether 1 is in the form of 1 or 4/4 or 8/8 or 234/234), the answer is always equal to the original number. 

Another way to check would be to simply enter 1/2 into a calculator, write down the answer. Next enter 5/8 into a calculator. If the answers are the same, they are equal.</span><span>
</span>
8 0
3 years ago
Read 2 more answers
Math problem I need help please it will be great if you help btw don't take this question down its is a school question
Maksim231197 [3]
The first question’s answer is the last option. And the range is 104
7 0
2 years ago
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