All categories

2 years ago

What is the volume of this prism

Mathematics

2 answers:

Lostsunrise [7]2 years ago

7 0

The answer is 36 cubic units. you just have to do L x W x H

Rainbow [258]2 years ago

4 0

Answer:

36 cubic units

Step-by-step explanation:

length x width x height

you don’t need to pay attention to 6.97 because that’s not the real height. The real height is 4 (the straight line)

3x3x4 = 36 cubic units

You might be interested in

Find the measure of the largest angle in the diagram below. (Type the<br> number only).

harkovskaia [24]

Answer: 112

2x+3x+10=180

5x=170

x=34

3x+10=112

6 0

3 years ago

Curtis decided to go on a road trip to Canada. On the first day of his trip, he drove for 10 hours and traveled 660 miles. At wh

Inga [223]

Answer:

Step-by-step explanation

This is very simple, 660/10

4 0

3 years ago

Do y’all know the answer to this?

Debora [2.8K]

Answer:

[C] 2

Step-by-step explanation:

You put it like this

4x+37= x+10

Then subtract x from both sides

3x+37= 10

Then subtract 37 from both sides

3x=-27

then you divide by 3

x=-9

<em>Theeeeeeeeeeeeeeen</em>

More work ahahah

you put both equations like this

4x+37+x+10

Combine like terms

5x+47

then substitute -9 for x

5(-9) +47

-45+47

8 0

2 years ago

Petra walked 4 1/5 km. Mandy walked 2 1/4 km less than Petra. How far did they walk altogether

Mkey [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give

LenaWriter [7]

Answer:

Equation of tangent will be $y=\frac{x}{e}$

Step-by-step explanation:

We have given the function $y=x^2e^{-x}$

We have to find the equation of tangent at the point $(1,\frac{1}{e})$

Equation of tangent is equal to $\frac{dy}{dx}$

So $\frac{dy}{dx}=x^2\frac{d}{dx}e^{-x}+e^{-x}\frac{d}{dx}2x=-x^2e^{-x}+2e^{-x}$

Now we have given point $(1,\frac{1}{e})$

So putting these points in the equation of tangent

$\frac{dy}{dx}=-1^2e^{-1}+2e^{-1}$

$\frac{dy}{dx}=\frac{1}{e}$

Now equation of tangent passing through $(1,\frac{1}{e})$

$y-\frac{1}{e}=\frac{1}{e}(x-1)$

$y=\frac{x}{e}-\frac{1}{e}+\frac{1}{e}=\frac{x}{e}$

4 0

2 years ago