4 floors with 6 class rooms each = 6*4 = 24 total class rooms.
24 class rooms x 34 students in each one = 816 total students.
Answer:
10 in
Step-by-step explanation:
There are two ways to work this problem, and they give different answers. The reason for that is that <em>the data shown in the diagram is not consistent</em>.
<u>Method 1</u>
Use the area to determine the base length. The area formula is ...
A = (1/2)bh
20 in^2 = (1/2)(b)(4 in)
(20 in^2)/(2 in) = b = 10 in
The missing side dimension is 10 inches.
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<u>Method 2</u>
Use the Pythagorean theorem to find the parts of the base, then add them up.
Left of the "?" we have ...
left^2 +4^ = 6^
left^2 = 36 -16 = 20
left = √20 = 2√5
Right of the "?" we have ...
right^2 +4^2 = 8^2
right^2 = 64 -16 = 48
right = √48 = 4√3
So, the base length is ...
base = left + right = 2√5 +4√3
base ≈ 11.400 in
The missing side dimension is 11.4 inches. (The area is 22.8 in^2.)
Given:
Measure of a cube = 1 unit on each side.
Dimensions of a space 2 units by 3 units by 4 units.
To find:
Number of cubes that can be fit into the given space.
Solution:
The volume of cube is:
Where, a is the side length of cube.
So, the volume of the cube is 1 cubic units.
The volume of the cuboid is:
Where, l is length, w is width and h is height.
Putting 
, we get
So, the volume of the space is 24 cubic units.
We need to divide the volume of the space by the volume of the cube to find the number of cubes that can be fit into the given space.
Therefore, 24 cubes can be fit into the given space.
10 I’m just going to write this cause it has to be 20 characters long to answer
The displacement vector is a vector which gives the point's current position with reference to other points apart from points from the origin. The given length here of the minute hand is the radius and the distance can be written as,
r∠θ
which means that the position can be described by the θ.
