Answer:
.9-1.5x
Step-by-step explanation:
Answer:
S={HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
Step-by-step explanation:
As can be seen in the Sample Tree attached, the eight elements in the sample space whose outcomes are all the possible head-tail sequences obtained in the three tosses are:
S={HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
Answer:
10/28
Step-by-step explanation:
Answer:
0.0098
Step-by-step explanation:
Given,
- Probability of test is positive if the person has disease, P(T/D)=0.99
Probability of test is negative if the person has disease,
P(T'/D) = 1-0.99 = 0.01
- Probability of test is negative if the person hasn't disease, P(T'/D')= 0.99
Probability of test is positive if the person hasn't disease,
P(T/D') = 1 - 0.99 = 0.01
- Probability of occurrence of disease, P(D) = 0.0001
Probability of not occurrence of disease,
P(D) = 1 - 0.0001 = 0.9999
Probability that test will be positive either disease is present or not,
P(T) = P(T/D).P(D)+P(T/D').P(D')
=0.99 x 0.0001 + 0.01 x 0.9999
= 0.000099 + 0.009999
= 0.010098
So, the probability that the person will have disease if the test is positive,


= 0.0098
So, the required probability will be 0.0098.
Answer:
Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
Step-by-step explanation:
Given:
3 x⁴ + 14 x² - 5 = 0 biquadratic equation
this equation is solved by a shift x² = t and get:
3 t² + 14 t - 5 = 0
t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6
t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6
t₁ = -5 or t₂ = 1 / 3
the solution t₁ = -5 is not accepted because it cannot be x² = -5
we accepted t₂ = 1 / 3
x² = 1 / 3 ⇒
x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
God is with you!!!