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2 years ago

All zeros of polynomial function 3x^4 +14x^2 -5

Mathematics

1 answer:

Marizza181 [45]2 years ago

5 0

Answer:

Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3

Step-by-step explanation:

Given:

3 x⁴ + 14 x² - 5 = 0 biquadratic equation

this equation is solved by a shift x² = t and get:

3 t² + 14 t - 5 = 0

t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6

t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6

t₁ = -5 or t₂ = 1 / 3

the solution t₁ = -5 is not accepted because it cannot be x² = -5

we accepted t₂ = 1 / 3

x² = 1 / 3 ⇒

x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3

God is with you!!!

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<em>New coordinates;</em>

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From the attached image, we can see that the coordinates are;

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Translating the polygon down by x units means the value of the y-coordinates will reduce by 4.

In a similar fashion, translation 5 units to the right means that the x-coordinates would increase by 5.

Applying these translation numbers to our coordinates, we will now have;

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B(-6 + 5, 2 - 4)

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Simplifying each of them gives us the new coordinates as;

A: (-1, 1)

B: (-1, -2)

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Read more at; brainly.com/question/4726090

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