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solong [7]
3 years ago
14

a woman is 5 times as old as her daughter in 15 years time to be two times as old as her daughter to find a mother's presentsage

​
Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

25 years.

Step-by-step explanation:

Given that a woman is 5 times as old as her daughter, while in 15 years time it will be two times as old as her daughter, to find a mother's presents age the following calculation must be performed:

5 x 5 = 25

25 + 15 = 40

40/2 = 20

5 + 15 = 20

Thus, the present age of the mother is 25 years, while that of her daughter is 5 years, with which the mother is five times the age of her daughter. In 15 years, the mother will be 40 and her daughter 20, with which she will only be twice her age.

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Answer:

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Step-by-step explanation:

Let's first expand the parentheses on both sides. Remember that when expanding parentheses, the result will be the sum of the products of the "outside number" with each of the "inside number".

On the left, the parenthetical expression is: -6(x + 4). Here, the outside term is -6 and the inside terms are x and 4. So:

-6(x + 4) = -6 * x + (-6) * 4 = -6x - 24

On the right, the parenthetical expression is: -5(x + 6). Here, the outside term is -5 and the inside terms are x and 6. So:

-5(x + 6) = -5 * x + (-5) * 6 = -5x - 30

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-6x - 15 > -5x - 30

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Thus the answer is x < 15.

Hope this helps!

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