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Katena32 [7]
3 years ago
13

How to start, there is also a second part to it but I'm pretty sure once I get the right formula I will be all set

Mathematics
2 answers:
Furkat [3]3 years ago
7 0
C=.35x + 9.50

.35 is the amount per check so you put the x next to it because that represents how may check you use plus 9.50 per month
hope this helps
Ilia_Sergeevich [38]3 years ago
3 0
F(c)=$9.50+$.35c

You start with your base fee and then add the $.35 per check which is $.35 times the amount of the check which is unknown.

Hope this helps.
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Write the linear equation that gives the rule for this table. x f(x) 1 22 2 23 3 24 4 25 Write your answer as an equation with f
densk [106]

Answer:

umm that doesn't make a whole lot of sense if its multiple choice can you give us the options please sorry I couldn't answer

Step-by-step explanation:

6 0
3 years ago
In the given diagram, find the values of x, y, and z.
anyanavicka [17]

Answer:

B) x=64, y=21, z=64

Step-by-step explanation:

X=180-116=64

Y cannot equal 115, and one angle is already 95, and that would put it over 180.  The only remaining choice for y=21

z=180-95-21=64

5 0
3 years ago
Help is appreciated!! ❤<br><br> Simplify the expression (5 + √3)(5 - √3)
Mademuasel [1]
Here’s a photo on how to do it! If you need help in more problems like this use a website called Symbolab!! It’s really helpful!!

5 0
3 years ago
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
Calculate the Compound interest for 18,000 for 2 years at 8% per
sp2606 [1]

Step-by-step explanation:

principal = 18000

Time = 3 yrs

Rate. = 8%.

CI. = ?

Now

CI = p ( 1+ R÷ 100) ^T

CI = 18000( 1+ 8÷ 100 ) ^ 2

CI = 20995.2

Hope it's is Right :-)

6 0
2 years ago
Read 2 more answers
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