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inna [77]
3 years ago
14

PLZ HELP

Mathematics
1 answer:
Karolina [17]3 years ago
3 0
The photo is not clear
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\bf f(x)=x^2+4x\qquad \cfrac{df}{dx}=2x+4\qquad \boxed{f''(x)=2}\impliedby 
\begin{array}{llll}
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there are no inflection points, because it never changes concavity, is just a constant and thus for any region over the x-axis, will always be a positive value, and thus is always "concave up".
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Lemur [1.5K]

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