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balandron [24]
3 years ago
11

Please help me answer this i will give brainliest and 5 star rating!!

Mathematics
2 answers:
marishachu [46]3 years ago
4 0

Answer:

63+45 divided by 12 + 55 times 12 + 95 (is what i think is the approximate length of the shadow)

Step-by-step explanation:

then after you do all this round it to the nearest foot

VARVARA [1.3K]3 years ago
3 0

Answer:

x = 77 ft

Step-by-step explanation:

55 ÷ 45 = 1.222222222

1.222222222 x 63 = 77

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The diagonals of a square are 4 meters long. the side of this square is equal to the diagonal of a second square. find the side
Svetllana [295]
Assume s is the side of the first square.
Let's find out the value of s:
4^2 = 2 × s^2 => s = 2.83 meters

Assume S is the side of the second square. Therefore 2.83^2 = 2 × S^2 => S = 2 meters.

The side of the second square is 2 meters
4 0
3 years ago
Hard question but would help me out
Alekssandra [29.7K]

Answer:

Critical value f(1)=2.

Minimum at (1,2), function is decreasing for 0 and increasing for x>1.

\left(3,\dfrac{4}{\sqrt{3}}\right) is point of inflection.

When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.

Step-by-step explanation:

1. Find the domain of the function f(x):

\left\{\begin{array}{l}x\ge 0\\x\neq 0\end{array}\right.\Rightarrow x>0.

2. Find the derivative f'(x):

f'(x)=\dfrac{(x+1)'\cdot \sqrt{x}-(x+1)\cdot (\sqrt{x})'}{(\sqrt{x})^2}=\dfrac{\sqrt{x}-\frac{x+1}{2\sqrt{x}}}{x}=\dfrac{2x-x-1}{2x\sqrt{x}}=\dfrac{x-1}{2x^{\frac{3}{2}}}.

This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is

f(1)=\dfrac{1+1}{\sqrt{1}}=2.

2. For 0 the derivative f'(x)<0, then the function is decreasing. For x>1, the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.

3. Find f''(x):

f''(x)=\dfrac{(x-1)'\cdot 2x^{\frac{3}{2}}-(x-1)\cdot (2x^{\frac{3}{2}})'}{(2x^{\frac{3}{2}})^2}=

=\dfrac{2x^{\frac{3}{2}}-2(x-1)\cdot \frac{3}{2}x^{\frac{1}{2}}}{4x^3}=\dfrac{2x^{\frac{3}{2}}-2\cdot\frac{3}{2}x^{\frac{3}{2}}+ 2\cdot\frac{3}{2}x^{\frac{1}{2}}}{4x^3}=

=\dfrac{-x+3}{4x^{\frac{5}{2}}}.

When f''(x)=0, x=3 and f(3)=\dfrac{3+1}{\sqrt{3}}=\dfrac{4}{\sqrt{3}}.

When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.

Point \left(3,\dfrac{4}{\sqrt{3}}\right) is point of inflection.

4 0
4 years ago
What is the distance between the point (1,4) and (3,7)
borishaifa [10]

Answer:

POINTS

Step-by-step explanation:

7 0
3 years ago
Given that when x is reduced by 17% the answer is y, express x in terms of y.
Dima020 [189]
X - 0.17 = y
 
add 0.17 to both sides

x = y + 0.17
3 0
3 years ago
Translate and solve: eight more than the product of three and a number is -13
Murrr4er [49]
Ok, so let’s take the given phrase.
Eight more than the product of 3 and a number is -13. A translation to numbers looks like this:
3x + 8 = -13
Now, let’s solve for x. We can start the process by subtracting 8 from both sides.
3x = -21
now, we will divide each side by 3 to isolate the variable, thus solving for x.
x = -7
6 0
4 years ago
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