Answer:
True
Step-by-step explanation:
<em><u>Option</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>,</u></em><em><u>2</u></em><em><u>5</u></em><em><u>4</u></em><em><u>.</u></em><em><u>3</u></em><em><u>4</u></em>
Answer:
Area =^r²
Area=22/7×9²
=3.14=81
=254.34
Answer:
Step-by-step explanation:
So given the three bits of information you can conclude a couple of things. The end behavior towards the right should be increasing and since there is only two turning points this means it was previously going down but had a turning point and starting going up, and before that it was going up and then started going down, those will be the two turning points. So on the left side it should be decreasing and the right side it should be increasing. The last peace of information tells you that at the second turning point, should be equal to 250k when it turned back up OR the y-intercept is 250k. Given all this information the answer should be the first graph in the first picture
Algebra:
A standard parabola is y = x^2. Its vertex is at (0,0)
You can change the position (or vertex) of the parabola.
To move a parabola across the x-axis, you can add or subtract a number from x WITHIN brackets of the ^2
eg. (x + 1)^2 will move the parabola across the x-axis. It will move is one unit to the LEFT (as the sign is opposite to the direction it moves ie. The sign it + but you move the whole parabola in the -ve direction).
Adding or subtracting a number from x OUTSIDE of the ^2 moves the parabola up or down the y-axis
eg. x^2 + 3 will move the parabola UP 3 units (the sign is the same as the direction it moves when the added/subtracted number is outside of the ^2 ie. the sign is positive so the parabola moves up in the positive direction)
From this, we can conclude that because (x + 1)^2 + 3, the vertex will be where x = -1 and where y = 3
Vertex : (-1,3)
Calculus:
f(x) = (x + 1)^2 + 3 = x^2 + 2x + 1 + 3 = x^2 + 2x + 4
Expanding the formular to make it easier to differentiate
f'(x) = 2x + 2
Differentiating (finding the formular the the gradiet of the parabola)
0 = 2x + 2
When the gradient is equal to zero, it must be the vertex
-2 = 2x
-2/2 = x
x = -1
Solve to give the x value at the vertex
f(x) = (x + 1)^2 + 3
= (-1 + 1)^2 + 3
Substitute x = -1 into original equatiom to find y value at the vertex
= (0)^2 + 3
= 0 + 3
= 3
Solve for y
Vertex : (-1,3)
