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Levart [38]
3 years ago
8

The formula for the surface area of a cube is A equal 6 s to the power of 2 comma where s is the side length. Cube X has a side

length of 1, and cube Y has a side length of 2. How much greater is the surface area of cube Y than cube X?
Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Answer:

Surface area of Cube Y is 3 times greater than the surface area of cube X

Step-by-step explanation:

Surface area of a cube,A = 6s²

Where,

s = side length

Cube X has a side length of 1,

Surface area of cube, X = 6s²

= 6 * 1²

= 6 * 1

= 6

cube Y has a side length of 2

Surface area of cube, Y = 6s²

= 6 * 2²

= 6 * 4

= 24

How much greater is the surface area of cube Y than cube X?

Surface area of Cube Y is 3 times greater than the surface area of cube X

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You have $30 to buy muffins. However, at the shop you can buy 1 muffin for $4. (a) Write an inequality from the above informatio
sattari [20]

Answer:

Let m be the number of muffins.

a) 4m <= 30

b) m <= 7.5, so the maximum number of muffins to buy is 7.

c) $4 × 7 = $28, so $2 will be left over.

8 0
1 year ago
Find two numbers between 1.4142133 and 1.41422
Naddik [55]

Hey there! I'm happy to help!

To find the number halfway between two numbers, you simply add them and then divide by two.

1.4142133+1.41422=2.8284333

2.8284333/2=1.41421665

That is one number in between these two. Now, we can find the number in between the middle number and the second number. This is another number in between our two numbers.

(1.41421665+1.41422)/2=1.414218325

You could keep on doing this and find tons of numbers in between these two.

Therefore, two numbers between 1.4142133 and 1.41422 are 1.41421665 and 1.414218325.

Have a wonderful day! :D

6 0
3 years ago
Can someone please help with this math question:)
Bingel [31]

<u>Solution</u><u>:</u>

The rationalisation factor for \frac{1}{ a -  \sqrt{b}  } is a + \sqrt{b}

So, let us apply it here.

\frac{1}{5 -  \sqrt{2} }

The rationalising factor for 5 - √2 is 5 + √2.

Therefore, multiplying and dividing by 5 + √2, we have

=  \frac{1}{5 -  \sqrt{2} }  \times  \frac{5 +  \sqrt{2} }{5 +  \sqrt{2} }  \\  =  \frac{5 +  \sqrt{2} }{(5 -  \sqrt{2})(5 +  \sqrt{2} ) }  \\  =  \frac{5 +  \sqrt{2} }{ {(5)}^{2} - ( \sqrt{2})^{2}   }  \\  =  \frac{5 +  \sqrt{2} }{25 -  2}  \\  =  \frac{5 +  \sqrt{2} }{23}

<u>Answer:</u>

<u>\frac{5 +  \sqrt{2} }{23}</u>

Hope you could understand.

If you have any query, feel free to ask.

5 0
2 years ago
Read 2 more answers
What is the side labeled x equal to, if y = 22?
miv72 [106K]
It is the same beacuse x is equal to y so x and y both equal 22
8 0
3 years ago
Read 2 more answers
Can someone plz answer B and C
Shkiper50 [21]

B. 
When two lines intersect they form two pairs of opposite angles.
Vertical angles are always congruent, which means that they are equal.
so  m<7 = m<8 or m<3y + 19 = m<5y-29


C. solve for y and measure <7 and <8

 3y + 19 = 5y-29
5y - 3y = 19+29
2y = 48
y = 24

so
5y-29 = 5(24) - 29 = 91
3y + 19 = 3(24) + 19 = 91

so <7 = 180 - 91 = 89
<7 = <8 = 89
4 0
3 years ago
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