Question

Find the sum of the zeros in the following equation: (2x-1)(x+8)(2x-4)(x-1)

Answer 1

Answer:

$-9\frac{1}{2}$

Step-by-step explanation:

$2x+1=0$

$2x=-1$

$x=-\frac{1}{2}$

$x+8=0$

$x=-8$

$2x-4=0$

$2x=4$

$x=2$

$x-1=0$

$x=1$

$1+2-8-\frac{1}{2}$

$=-1-8\frac{1}{2}$

$=-9\frac{1}{2}$

Sum of fractions $=-9\frac{1}{2}$