Consider that,
x^2+4x+4 = (x+2)(x+2)
x^2+7x+10 = (x+2)(x+5)
Dividing those expressions leads to
(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)
The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.
905 = 9 hundreds + 0 tens + 5 ones
or 8 hundreds, 10 tens, 5 ones
425 = 4 hundreds, 2 tens, 5 ones
8 hundreds, 10 tens, 5 ones
4 hundreds, 2 tens, 5 ones
---------------------------------------subtract
4 hundreds, 8 tens, 0 ones = 480......(905 - 425 = 480)