Question

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Answer 1

Answer:

(d.) $18x^3-27x^2y$

Step-by-step explanation:

When given the following equation,

$(3x)^2(2x-3y)$

Systematically perform the operations. Use the order of operations, the order of operations states the following,

1. Parenthesis

2. Exponents/ radicals

3. Multiplication/ Division

4. Addition/ Subtraction

Remember, when performing an exponential operation, one multiplies the base by itself the number of times the exponent indicates. In the given equation, perform the exponent by multiplying the base (3x) by itself twice.

$(3x)^2(2x-3y)\\\\(3x)(3x)(2x-3y)\\\\(9x^2)(2x-3y)$

Now distribute, multiply every term inside the parenthesis by the term outside of it

$(9x^2)(2x-3y)\\\\(9x^2)(2x) + (9x^2)(-3y)$

Simplify,

$18x^3-27x^2y$

Therefore the solution is (d.) $18x^3-27x^2y$

Answer 2

Answer:

d. 18x^3-27x^2y

Step-by-step explanation:

(3x)^2(2x-3y)

work out the first term

9x^2(2x-3y)

distribute

18x^3-27x^2y