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bogdanovich [222]
3 years ago
15

Convert 12+4y =-4x to slope intercept form

Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer:

y=mx+b

y=-x-3

Step-by-step explanation:

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PLEASE HELP IM DESPERATE<br><br> ALL I NEED IS FOR SOMEONE TO ANSWER NUMBERS 7, 8, AND 9
andrezito [222]

Answer:

The answer to 9 is below

Step-by-step explanation:

2(L + W) = P

2(W + 5a - b) = 16a + 2b

2(W + 5a - b) = 2(8a + b)

W + 5a - b = 8a + b

W = 3a + 2b

8 0
3 years ago
Solve using system by elimination:<br> -3x + 4y = -18<br> x = -2y - 4
MariettaO [177]

Answer:

x=2 and y=−3

Step-by-step explanation:

Use math papa's systems of equations calculator that shows work!

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6 0
3 years ago
Read 2 more answers
find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2
Alexxandr [17]

The surface is parameterized by

\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k

and the normal to the surface is given by the cross product of the partial derivatives of \vec s :

\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}

It looks like you're given

\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}

Then the normal vector is

\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k

Now, the point (2, 2, 0) corresponds to u and v such that

\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}

and solving gives u = v = 1, so the normal vector at the point we care about is

\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k

Then the equation of the tangent plane is

\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath +  (z-0)\,\vec k\right) = 0

-4(x-2) + 2(y-2) - 4z = 0

\boxed{2x - y + 2z = 2}

6 0
2 years ago
HELP ME WIT THIS PLEASE no
Leokris [45]

Answer:

Drews answer was correct

Step-by-step explanation:

try using desmos graphing calculator it helps

7 0
3 years ago
A.) Prove that the ratio of two rational numbers must be rational.
Luda [366]

Answer:

v — Prove that (ax + b)/(cx + d) is irrational if and only if ad = bc. ... If b = 0, we have (ax + b)/(cx + d) = 0 is rational; if c = 0, since ... nonzero integers m, n ∈ Z. Then we have ... Proof. We prove by induction. When n = 1, both sides are 1/2 hence the ... So there are less than (k + 1)(2k + 1)k+1 (actually muc

Step-by-step explanation:

c — Prove that (ax + b)/(cx + d) is irrational if and only if ad = bc. ... If b = 0, we have (ax + b)/(cx + d) = 0 is rational; if c = 0, since ... nonzero integers m, n ∈ Z. Then we have ... Proof. We prove by induction. When n = 1, both sides are 1/2 hence the ... So there are less than (k + 1)(2k + 1)k+1 (actually muc

4 0
3 years ago
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