Answer:
v — Prove that (ax + b)/(cx + d) is irrational if and only if ad = bc. ... If b = 0, we have (ax + b)/(cx + d) = 0 is rational; if c = 0, since ... nonzero integers m, n ∈ Z. Then we have ... Proof. We prove by induction. When n = 1, both sides are 1/2 hence the ... So there are less than (k + 1)(2k + 1)k+1 (actually muc
Step-by-step explanation:
c — Prove that (ax + b)/(cx + d) is irrational if and only if ad = bc. ... If b = 0, we have (ax + b)/(cx + d) = 0 is rational; if c = 0, since ... nonzero integers m, n ∈ Z. Then we have ... Proof. We prove by induction. When n = 1, both sides are 1/2 hence the ... So there are less than (k + 1)(2k + 1)k+1 (actually muc
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![D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}](https://tex.z-dn.net/?f=D%28x%3B%5C%20y%29%5C%5C%5C%5C%5Cvec%7BED%7D%3D%5Bx-%28-2%29%3B%5C%20y-4%5D%3D%5Bx%2B2%3B%5C%20y-4%5D%5C%5C%5C%5C%5Cvec%7BED%7D%3D%5Cvec%7BBE%7D%5C%20therefore%5C%5C%5C%5C%20%5C%20%5Bx%2B2%3B%5C%20y-4%5D%3D%5B4%3B%5C%20-6%5D%5Cto%20x%2B2%3D4%5C%20and%5C%20y-4%3D-6%5C%5C%5C%5Cx%3D2%5C%20and%5C%20y%3D-2%5C%5C%5C%5CAnswer%3A%5C%20%5Cboxed%7BA.%5C%20%282%3B%5C%20-2%29%7D)
