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Softa [21]
3 years ago
5

What is the density of a rock that has a mass of 555 g and a volume of 101.1 cm?

Chemistry
2 answers:
marin [14]3 years ago
7 0

Answer:

the volume should be in cubic cm so I assumed that you wanted to write the same . then the answer is 5489.07 kg/m^3

Anuta_ua [19.1K]3 years ago
3 0

Answer:

\boxed {\boxed {\sf d\approx5.49 \ g/cm^3}}

Explanation:

Density can be found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the rock is 555 grams and the volume is 101.1 cubic centimeters.

m=555 \ g \\v= 101.1 \ cm^3

Substitute the values into the formula.

d=\frac{555 \ g}{101.1 \ cm^3}

Divide.

d=5.48961424 \ g/cm^3

Let's round to the nearest hundredth to make the answer more concise.

The 9 in the thousandth place tells us to round up. In the tenth place, the 8 will become a 9.

d\approx5.49 \ g/cm^3

The density of the rock is about <u>5.49 grams per cubic centimeter.</u>

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100.0 g water cools from 85.0°C to 20.0°C. If the specific heat of water is 4.18 J/g°C, calculate the change in energy.
Natali5045456 [20]

Answer:

-27.2 kJ

Explanation:

We can use the heat-transfer formula. Recall that:

\displaystyle q = mC\Delta T

Where <em>m</em> is the mass, <em>C</em> is the substance's specific heat, and Δ<em>T</em> is the change in temperature.

Hence substitute:


\displaystyle \begin{aligned} q & = (100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(20.0\text{ $^\circ$C} - 85.0\text{ $^\circ$C}) \\ \\ & =(100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(-65.0\text{ $^\circ$C}) \\ \\  & = -2.72\times 10^4\text{ J} = -27.2\text{ kJ}\end{aligned}

Therefore, the cooling of the water <em>released</em> about 27.2 kJ of heat.

5 0
3 years ago
What is the molarity of the two solutions <br> 0.150 mol of NaOH in 1.80 L of solution
padilas [110]
1 mole of MgS = 24.3 + 32.1 = 56.4 g

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4 years ago
A student dissolves a spoon full of table salt (sodium chloride) in a glass of water.
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Answer:

Aqueous sodium ions, Aqueous chloride ions

Explanation:

Sodium chloride dissociates into Na+ and Cl- ions in water

Sodium chloride crystals may also be present in case of saturated solution

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