What is the density of a rock that has a mass of 555 g and a volume of 101.1 cm?

Chemistry

2 answers:

marin [14]3 years ago

7 0

Answer:

the volume should be in cubic cm so I assumed that you wanted to write the same . then the answer is 5489.07 kg/m^3

Anuta_ua [19.1K]3 years ago

3 0

Answer:

$\boxed {\boxed {\sf d\approx5.49 \ g/cm^3}}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the rock is 555 grams and the volume is 101.1 cubic centimeters.

$m=555 \ g \\v= 101.1 \ cm^3$

Substitute the values into the formula.

$d=\frac{555 \ g}{101.1 \ cm^3}$

Divide.

$d=5.48961424 \ g/cm^3$

Let's round to the nearest hundredth to make the answer more concise.

The 9 in the thousandth place tells us to round up. In the tenth place, the 8 will become a 9.

$d\approx5.49 \ g/cm^3$

The density of the rock is about 5.49 grams per cubic centimeter.

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100.0 g water cools from 85.0°C to 20.0°C. If the specific heat of water is 4.18 J/g°C, calculate the change in energy.

Natali5045456 [20]

Answer:

-27.2 kJ

Explanation:

We can use the heat-transfer formula. Recall that:

$\displaystyle q = mC\Delta T$

Where m is the mass, C is the substance's specific heat, and ΔT is the change in temperature.

Hence substitute:

$\displaystyle \begin{aligned} q & = (100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(20.0\text{ $^\circ$C} - 85.0\text{ $^\circ$C}) \\ \\ & =(100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(-65.0\text{ $^\circ$C}) \\ \\ & = -2.72\times 10^4\text{ J} = -27.2\text{ kJ}\end{aligned}$