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3 years ago

Refer to aqueous solutions containing 1:1 mole ratios of the following pairs of substances. Assume all concentrations are 1 M.

Chemistry

2 answers:

LekaFEV [45]3 years ago

7 0

Answer:

c) HCl and NaCl

Explanation:

Since all the solutions are on a 1:1 mole ratio the comparison is straight forward.

The lowest pH will be for solution c) which has a strong acid, HCl, which ionizes 100 % and the neutral salt NaCl (which is neutral since it is derived from the reaction of the strong acid HCl and the strong base NaOH).

Solutions a) and b) are buffers of the weak base NH₃ and its conjugate acid NH₄⁺ and weak acid H₃PO₄ and its conjugate weak base NaH₂PO₄ respectively.

Solution c) is a basic solution being a mixture of the weak base NH₃ and the strong base NaOH

Solution e) is a mixture of a weak base NH₂ and weak acid HC₂H₃O₂

denis23 [38]3 years ago

7 0

Answer:

HCl and NaCl option c

Explanation:

According to the pH scale interpretation a lower pH means that its is more acidic, while a higher pH means that it is more basic.

Simply put a pH of 7 is neutral. A pH less than 7 is acidic. A pH greater than 7 is basic.

From the question above c fits in the option with the lower pH meaning its a strong acid and it tends more towards 0 than 7.

A solution, containing a buffer, is one that maintains a relatively constant pH.

NH3 and NH4Cl ;H3PO4 and NaH2PO4 are an acid/base conjugate pair each. They will make an excellent buffer.

NaOH and NH3 would rather make a slightly basic mixture

NH2 and HC2H3O2 (acetic acid) slightly basic mixture ..

Solution c has the lowest pH.

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A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44

d1i1m1o1n [39]

Answer:

300.9mL

Explanation:

Given parameters:

V₁ = 280mL

T₁ = 22°C

T₂ = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

it is mathematically expressed as;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

We need to convert the temperature to kelvin;

T₁ = 22°C = 22 + 273 = 295K

T₂ = 44°C = 44 + 273 = 317K

Input the parameters and solve;

$\frac{280}{295}$ = $\frac{V_{2} }{317}$

V₂ x 295 = 280 x 317

V₂ = 300.9mL

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3 years ago

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Answer:

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2 years ago

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For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4?

jekas [21]

In this question given concerning the atom's electron, the number of energy sublevels present in the principal energy level n = 4 is to be determined. For this matter, it should be remembered that the number of sublevels of a certain principal energy level is equal to n. For this item, the number of sublevels is also 4. That is s, p, d and f.

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3 years ago

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Write both answers to at least two decimal places. Calculate the pH of a 0.160 M solution of KOH.Part 2 (1 point) Calculate the

Evgen [1.6K]

To calculate the pH of a solution, we first need to find the concentration of hydronium ions in the solution. Since KOH is a strong base, it dissociates completely in water to produce hydroxide ions (OH-) and potassium ions (K+).

The concentration of hydronium ions in a solution of KOH can be calculated using the concentration of hydroxide ions and the equilibrium constant for water, which is equal to 1.00 x 10^-14 at 25 degrees Celsius.

The concentration of hydroxide ions in a 0.160 M solution of KOH is equal to the concentration of KOH, which is 0.160 M. The concentration of hydronium ions in the solution can be calculated using the equation below:

[H3O+] = (1.00 x 10^-14) / [OH-]

Substituting the concentration of hydroxide ions into the equation above, we get:

[H3O+] = (1.00 x 10^-14) / (0.160 M) = 6.25 x 10^-13 M

To calculate the pH of the solution, we need to take the negative logarithm of the concentration of hydronium ions. This can be done using the equation below:

pH = -log([H3O+])

Substituting the concentration of hydronium ions into the equation above, we get:

pH = -log(6.25 x 10^-13) = 12.20

The pH of a 0.160 M solution of KOH is 12.20.

To calculate the pOH of a solution, we first need to find the concentration of hydroxide ions in the solution. Since we already calculated this value above, we can simply use the concentration of hydroxide ions we found earlier: 0.160 M.

To calculate the pOH of the solution, we need to take the negative logarithm of the concentration of hydroxide ions. This can be done using the equation below:

pOH = -log([OH-])

Substituting the concentration of hydroxide ions into the equation above, we get:

pOH = -log(0.160 M) = 1.80

The pOH of a 0.160 M solution of KOH is 1.80.

Learn more about pH:
brainly.com/question/28864035

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7 0

10 months ago

One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal

kenny6666 [7]

Answer:

Lithium oxide, Li₂O.

Explanation:

Hello!

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

$M_2O+H_2\rightarrow 2M+H_2O$

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

$5.00gM_2O*\frac{1molM_2O}{(2*X+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{XgM}{1molM}=2.32gM$

Thus, we perform the operations in order to obtain:

$\frac{10X}{(2X+16)}=2.32$

So we solve for x as shown below:

$10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol$

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.

Best regards!

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2 years ago