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anzhelika [568]
3 years ago
11

Use synthetic division to divide x^3-8x^2+9x-5 by x-3

Mathematics
2 answers:
givi [52]3 years ago
6 0

Answer:

x2 - 5x - 6 + -23/x-3Step-by-step explanation:

ohaa [14]3 years ago
6 0

Answer:

x^2 - 6x - 6, remainder -23

Step-by-step explanation:

Start like this:

              3    |     1      -8      9     -5

                    |

                   --------------------------------      

First step is to copy the 1 to below the line.

              3    |     1      -8      9     -5

                    |

                   --------------------------------      

                           1

Now multiply 3 by 1 and write below the -8. Then add the product to the -8 and write the sum below the line.

              3    |     1      -8      9     -5

                    |              3

                   --------------------------------      

                           1     -5

Now multiply 3 by -5 and write below the 9. Then add the product to the 9 and write the sum below the line.

              3    |     1      -8      9     -5

                    |              3    -15

                   --------------------------------      

                           1     -5     -6

Now multiply 3 by -6 and write below the -5. Then add the product to the -5 and write the sum below the line.

              3    |     1      -8      9     -5

                    |              3    -15    -18

                   --------------------------------      

                           1     -5     -6     -23

Answer: x^2 - 6x - 6, remainder -23

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If you roll two number cubes ,what is the probability of their sum being 9 or higher?
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Answer:

5/18

Step-by-step explanation:

When two cubes are rolled there are 36 possibilities

Each dice has 6 equally like outcomes so possibilities are

(1,1)  (1,2)          (1,3)          (1,4)         (1,5)         (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

Now we look at the pair that has sum equal to 9

(3,6) (4,5) (5,4) (6,3) that has sum of 9

Probability of sum is 9 = \frac{4}{36}

we look at the pairs that has sum greater than 9

(4,6) (5,5)(5,6) (6,4)(6,5)(6,6)

Probability of sum greater than 9 = \frac{6}{36}

Probability of sum 9 or higher = P(sum 9) + P(greater than 9)

= \frac{4}{36}+\frac{6}{36}= \frac{10}{36}=\frac{5}{18}



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