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anzhelika [568]
3 years ago
11

Use synthetic division to divide x^3-8x^2+9x-5 by x-3

Mathematics
2 answers:
givi [52]3 years ago
6 0

Answer:

x2 - 5x - 6 + -23/x-3Step-by-step explanation:

ohaa [14]3 years ago
6 0

Answer:

x^2 - 6x - 6, remainder -23

Step-by-step explanation:

Start like this:

              3    |     1      -8      9     -5

                    |

                   --------------------------------      

First step is to copy the 1 to below the line.

              3    |     1      -8      9     -5

                    |

                   --------------------------------      

                           1

Now multiply 3 by 1 and write below the -8. Then add the product to the -8 and write the sum below the line.

              3    |     1      -8      9     -5

                    |              3

                   --------------------------------      

                           1     -5

Now multiply 3 by -5 and write below the 9. Then add the product to the 9 and write the sum below the line.

              3    |     1      -8      9     -5

                    |              3    -15

                   --------------------------------      

                           1     -5     -6

Now multiply 3 by -6 and write below the -5. Then add the product to the -5 and write the sum below the line.

              3    |     1      -8      9     -5

                    |              3    -15    -18

                   --------------------------------      

                           1     -5     -6     -23

Answer: x^2 - 6x - 6, remainder -23

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Answer:

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Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

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Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

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Answer:

a) 0.84% of students scored over 32

b) 29.12% of students scored under 17​

c) 70.04% of students scored between 17 and 32.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 19.8, \sigma = 5.1

a) About what percent of students scored over 32​?

This is 1 subtracted by the pvalue of Z when X = 32. So

Z = \frac{X - \mu}{\sigma}

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Z = 2.39

Z = 2.39 has a pvalue of 0.9916

1 - 0.9916 = 0.0084

So 0.84% of students scored over 32

​b) About what percent of students scored under 17​?

This is the pvalue of Z when X = 17. So

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So 29.12% of students scored under 17​

c) About what percent of students scored between 17 and 32​?

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 12. So

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Z = \frac{17 - 19.8}{5.1}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

0.9916 - 0.2912 = 0.7004

70.04% of students scored between 17 and 32.

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