I believe the answer is: <span>the allocation method
production possibilities graph could only include the factors that can be projected after doing combination of various products' production.
Allocation method only play role in the technique that can be used to produce the products and cannot be considered as data projection from the production
</span>
Answer:
a. 2019 Operating cash flow
Welland Co. Operating Cash Flow for 2019
Particular Amount $
Sales 162500
Cost of goods sold 80000
Other Expenses 3300
Depreciation 9000 <u>92,300</u>
EBIT 70200
Less: Taxes 22295
Add :Depreciation <u>9000</u>
Operating Cash Flow $<u>56905</u>
b. Cash flow to creditors
Interest paid 6500
Add: Loan raised <u>7700</u>
Cash flow to creditors <u>14200</u>
c. Cash flow to Stockholders
Dividends Paid 8150
Less: Net Equity Raised <u>4500</u>
Cash flow to Stockholders <u>$3650</u>
d. Change in Net working Capital = Change in Current Assets - Change in Liabilities
Figures for Current Asset was not given, rather the Net Fixed asset is given $21,100 which is not a current asset.
Answer:
$28,300
Explanation:
Missing word: "<em>Calculate free cash flow."</em>
<em />
Free cash flow = Operating cash flow - Capital expenditures - Dividends
Free cash flow = $361,200 - $206,000 - $126,900
Free cash flow = $28,300
So, the Free cash flow of Hinck Corporation is $28,300.
Three essential <span>principles of test construction are:
1. consistency. It refers to the consistency </span><span>between the goal of the subject, course, and the methods of teaching goals. Also consistency between the methods and what the test measures. </span><span>
2. validity. Validity refers to t</span>he ability of a test to measure what it was designed to measure. It can be material od skill.
3. reliability. The <span>test must be constructed in such a way that it will produce reliable, consistent results .</span>
Answer:
![A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%20%281.12%29%5E4%7D%7B%281.12%29%5E4%20-1%7D%5D)
![A = 28000 [\frac{0.12*1.574}{1.574-1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%2A1.574%7D%7B1.574-1%7D%5D)

So then the annual pay would be $ 9218.564 for this case
Explanation:
For this question we can use the Equivalent annual value (A) given by the following expression:
![A = PV [\frac{i (1+i)^t}{(1+i)^t -1}]](https://tex.z-dn.net/?f=%20A%20%3D%20PV%20%5B%5Cfrac%7Bi%20%281%2Bi%29%5Et%7D%7B%281%2Bi%29%5Et%20-1%7D%5D)
Where
represent the pesent value
since the rate is yearly
since we have 4 years to pay
So then we have everything to replace and we got:
![A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%20%281.12%29%5E4%7D%7B%281.12%29%5E4%20-1%7D%5D)
![A = 28000 [\frac{0.12*1.574}{1.574-1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%2A1.574%7D%7B1.574-1%7D%5D)

So then the annual pay would be $ 9218.564 for this case
And this amount would be paid each year in order to pay all the money after 4 years.