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2 years ago

Jada has 60% of her goal of $70 saved for her trip.

Mathematics

2 answers:

Amiraneli [1.4K]2 years ago

4 0

Answer:

60% of $70 is $42, so i think its $42

zaharov [31]2 years ago

4 0

Answer:

Jada has saved $36

Step-by-step explanation:

60% of $60 is the question

0.6 × $60 is $36

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Need help please, does any one know how to do this

ziro4ka [17]

Answer:

(6-u)/(2+u)
8/(u+2) -1
-u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

(-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

(6 -u)/(u +2)

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

4) You can also multiply numerator and denominator by some constant, say 3:

-(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

(1+x^2)(6 -u)/((1+x^2)(u+2))

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3 years ago

An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th

antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

$200 \times a + 100 \times c = 2100$

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

Thus the cost of children’s ticket is $ 5

6 0

3 years ago

What is 49 divided by 3 plus 87

ozzi

Answer: 103.3

Step-by-step explanation:

Divide 49/3 and u get 16.3333333333. Then add 16.3333333333 and 87 and get 103.333333333. Round 103.333333333 to the nearest tenth and get 103.3

Hope this helps! #BaconSquad

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3 years ago

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belka [17]

Answer:

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2 years ago

Algebra I<br> Evaluate each function. h ( n ) = 2 n − 5 ; Find h ( 2 )

slavikrds [6]

Answer:

$h ( 2 ) = - 1$

Step-by-step explanation:

<u>Two-Variable Functions</u>

A function expresses the relation between two variables in such a way that for each input for the independent variable n, there one and only one value for the function h(n). If it's explicitly given as an equation, then we can use values for n as we wish, and compute the different values of h(n).

The question provides the following function

$h ( n ) = 2 n - 5$

We are required to find h(2), which can be computed by replacing n by the value of 2

$h ( 2 ) = 2 (2) - 5$

$h ( 2 ) = 4 - 5$

$h ( 2 ) = - 1$

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2 years ago